Consider an experiment with sample space S = {A,B,C}. If P(A)=0.6, P(B)=0.2, and P(C)=0.2, then (a) P( B or C ) = (b) P( A and C ) =
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Consider an experiment with
If P(A)=0.6, P(B)=0.2, and P(C)=0.2, then
(a) P( B or C ) =
(b) P( A and C ) =
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- The records of a light bulb manufacturer show that, when the manufacturing machinery is working correctly, the defect rate (due to imperfections in the material used) is 1%. The manufacturer's control department periodically tests samples of the bulbs, and when 1.25% or more are defective, they call repair technicians for service. The control department is going to take a random sample of 4400 light bulbs. Let p be the proportion of defective light bulbs in the sample assuming the machinery is working correctly. A) find the mean of p b)find the standard deviation of p c)Compute an approximation for P≥p0.0125, which is the probability that, assuming the machinery is working correctly, the repair technicians will be called. Round your answer to four decimal places.The records of a light bulb manufacturer show that, when the manufacturing machinery is working correctly, the defect rate (due to imperfections in the material used) is 1%. The manufacturer's control department periodically tests samples of the bulbs, and when 1.25% or more are defective, they call repair technicians for service. The control department is going to take a random sample of 4400 light bulbs. Let p be the proportion of defective light bulbs in the sample assuming the machinery is working correctly. Answer the following. (If necessary, consult a list of formulas.) (a) Find the mean of p. (b) Find the standard deviation of p. (c) Compute an approximation for P(P ≥ 0.0125), which is the probability that, assuming the machinery is working correctly, the repair technicians will be called. Round your answer to four decimal places.. List the 10 possible samples (without replacement) of size 2 that can be obtained from the population of five officials. Lieutenant Governor (L) Secretary of State (S) Attorney General (A) Representative (R) Press Secretary (P) b. If a simple random sampling procedure is used to obtain a sample of two officials, what are the chances that it is the first sample on your list in part (a)? the secondsample? the tenth sample?
- A survey is conducted to determine if there is a difference in the proportion of students, parents, and What are the appropriate hypotheses to determine if the distribution of response differs among these three populations? teachers who volunteer at least once a month. To investigate, a random sample of 45 students, 25 parents, and 12 teachers was selected from a large high school. The data are displayed in the table. O Ho: There is a difference in the distribution of responses among these three populations. Hg: There is no difference in the distribution of Student Parent Teacher responses among these three populations. 12 O Ho: There is no difference in the distribution of Yes 24 Volunteer? responses among these three populations. Hg: There is a difference in the distribution of No 21 13 response among these three populations. Họ: There is no association between the type of person who is surveyed and the response. Hạ: There is an association between the type of person who is surveyed…The candy company that makes M&M's claims that 10% of the M&M's it produces are green. Suppose that the candies are packaged at random, and the small bags contain 25 M&M's. When we randomly pick a bag of M&M's, we may assume that this represents a simple random sample of size n = 25. Suppose that in a randomly selected small bag of M&M's, there are 5 green M&M's. What is the value of the standard error of p? 0.08 0.0063 0.0794 O 0.10Sample space S is partitioned into E1, E2, E3, and E4 such that P(E,) = 0.28, P(E2) = 0.03, and P(E3) = 0.48. %3D a. Find P(E4). b. Find the odds in favor of and the odds against E, occurring. ..... a. P(E4) = (Simplify your answer.) %3D b. The odds in favor of E4 occurring, in lowest terms, are (Type whole numbers.) The odds against E4, in lowest terms, are (Type whole numbers.)
- 46% of all statistics classes require an advanced calculator and 38% require the use of a computer that has statistical software. Of the classes that require an advanced calculator, 18% also require the use of a computer. If a statistics course is selected at random find A. P(Advanced Calculator) = [ Select ] ["0.57", "0.38", "0.18", "0.46"] B. P(Statistical Software) = [ Select ] ["0.38", "0.57", "0.46", "0.18"] C. P(Require an Advanced Calculator and Statistical Software) = [ Select ] ["0.1259", "0.1748", "0.0828", "0.8335"] D. P(Require an Advanced Calculator GIVEN Require Statistical Software) = [ Select ] ["0.3515", "0.18", "0.2184", "0.9716"]Suppose that we have a sample space with five equally likely experimental outcomes: E1, E2, E3, E4, E5. Let A = {E1, E4} B = {E2, E3} C = {E2, E4, E5}. (a) Find P(A), P(B), and P(C). P(A) = P(B) = P(C) = (b) Find P(A ∪ B). P(A ∪ B) = Are A and B mutually exclusive? They mutually exclusive. (c) Find AC. (Enter your answer in set notation.) AC = Find CC. (Enter your answer in set notation.) CC = Find P(AC) and P(CC). P(AC) = P(CC) = (d) Find A ∪ BC. (Enter your answer in set notation.) A ∪ BC = Find P(A ∪ BC). P(A ∪ BC) = (e) Find P(B ∪ C). P(B ∪ C) =p3
- Refer to the following scenario. A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these social outreach programs should be located based on the percentage of residents living below the poverty line in each region of the city. He takes a simple random sample of 120 people living in Gastown and finds that 21 have an annual income that is below the poverty line. For each of the following statements, specify whether the statement is a correct interpretation of the 95% confidence interval for the true proportion of Gastown residents living below the poverty line. A. 17.50% (21/120) of Gastown residents are living below the poverty line. ? B. There is a 95% probability that the true proportion of Gastown residents who are living below the poverty line equals 21/120. C. If another random sample of 120 Gastown residents is drawn, there is a 95% probability that the sample proportion of Gastown residents who are living below…Refer to the following scenario. A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these social outreach programs should be located based on the percentage of residents living below the poverty line in each region of the city. He takes a simple random sample of 123 people living in Gastown and finds that 24 have an annual income that is below the poverty line. For each of the following statements, specify whether the statement is a correct interpretation of the 95% confidence interval for the true proportion of Gastown residents living below the poverty line. A. 19.51% (24/123) of Gastown residents are living below the poverty line. ? + B. There is a 95% probability that the true proportion of Gastown residents who are living below the poverty line equals 24/123. ? + C. If another random sample of 123 Gastown residents is drawn, there is a 95% probability that the sample proportion of Gastown residents who are living…Refer to the following scenario. A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these social outreach programs should be located based on the percentage of residents living below the poverty line in each region of the city. He takes a simple random sample of 127 people living in Gastown and finds that 20 have an annual income that is below the poverty line. For each of the following statements, specify whether the statement is a correct interpretation of the 95% confidence interval for the true proportion of Gastown residents living below the poverty line. A. 15.75% (20/127) of Gastown residents are living below the poverty line. ? B. There is a 95% probability that the true proportion of Gastown residents who are living below the poverty line equals 20/127. ? C. If another random sample of 127 Gastown residents is drawn, there is a 95% probability that the sample proportion of Gastown residents who are living…
