c) How does the classical kinetic energy of the free electron compare in magnitude with the result youobtained in the previous part?Consider an electron confined to a box of length L = 436 pm.(a) A transition between energy levels can be induced by absorption of light whose photonenergy matches the energy difference between the levels. Find the energy differencebetween the levels corresponding to n = 4 and n = 5 of this same box, and compute thewavelength of light (in m) that would cause a transition between them. What portion ofthe electromagnetic spectrum is this light?(b) For another box, suppose that this same transition (n = 4 →→ 5) was observed at awavelength of 232 nm. How long is this box in pm?

Given: An electron is confined to a box with length, L=436 pm. A transition is made between the n=4…

Answered: Consider an electron confined to a box…

Similar questions

Just like the optical part of the spectrum, radio waves can be described in terms of photons - although they can be very difficult to detect. Consider the photons in radio waves from an FM station that has a 88.3-MHz broadcast frequency. Find the energy in joules of a photon in the radio waves.
i can confirm the answer of 3.08*10^4 is wrong
A light wave of a particular frequency hits a metal. The light wave is made of discrete photons, each with energy hf = hc/λ. An electron will either completely absorb a photon, or not at all. An electron in a metal needs an energy to leave the metal -- the work function (W). For the W given, calculate the maximum light wavelength (in nm) that will eject an electron. I will use electron-volts (eV) for energy, because the computer gives me trouble with very low numbers. hc = 1240 eV nm W = 3.9 eV
A series of experiments by Clinton Davisson and Lester Germer in the 1920s gave a clear indication of the wave nature of matter. The investigators scattered a relatively low energy electron beam from a nickel crystal. They found very strong reflections at certain angles that varied with the energy of the electron beam. The strong reflections were analogous to those observed in x-ray diffraction. The angles at which the intensity of the reflected beam peaks agreed with the Bragg condition if the electrons wereassumed to have a wavelength given by the de Broglie formula. This was conclusive experimental proof of the wave nature of the electron. Davisson and Germer used an electron beam that was directed perpendicular to the surface, as shown. They observed a particularly strong reflection, corresponding to m = 1 in the Bragg condition, at φ = 50°. At this angle, the spacing between the scattering planes was d = 0.091 nm. What is the de Broglie wavelength of electrons in the beam?A. 0.077…
An electron is moving at 1.00 km per second. What is it's de Broglie wavelength? Show the algebraic form of all equation(s) applied and report your final answer with the correct units and number of significant figures.
A hydrogen atom is initially in the n = 6 state. It drops to the n = 2 state, emitting a photon in the process. (a) What is the energy (in ev) of the emitted photon? Enter a number. ergy of a hydrogen atom related to the quantum number n? What is the atom's initial energy? Its final energy? From these values and conservation of energy, what is the photon's energy? ev (b) What is the frequency (in Hz) of the emitted photon? Hz (c) What is the wavelength (in um) of the emitted photon? um
In the classical limit calculate the wavelength corresponding to an electron with the energy of 99 kev (kiloelectronvolt). Give your answer in Angstrom (10-10 1.6x10-10 m, then write 1.6 as your answer). This m, for example, if the answer is should give you a good idea why one can use a crystal lattice with an average interatomic distance of around 1010 m to observe electron diffraction.
I need help with this question. Originally I got 3 degrees for the answer, but it appears that this is incorrect and I don't know what went wrong. Here is the question: Electrons with an energy of 0.610 eV are incident on a double slit in which the two slits are separated by 60.0 nm. Electron speed is 4.63e+05 m/s and the de Broglis wavelength of the electrons is 1.57 nm. What is the angle between the two second-order maxima in the resulting interference pattern. I really appreciate the help!