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Consider an electric field E= Eo, where Eo is a constant.
The flux through the shaded area (as shown in the figure) due
to this field is
30
(a,0,a)
S DV
(a) 2E₂a²
(c) E₂a²
XK
1²
(a,a,a)
(0,0,0) (0,a,0)
→y
(b) √2Ea²
Ea²
(d)
√2
SERIK
6

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