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Consider AGHJ in the figure below. The perpendicular bisectors of its sides are KN, LN, and MN. They meet at a single point N. (In other words, N is the circumcenter of AGHJ.) Suppose LN=78, GJ=94, and GN=130. Find HN, LJ, and GK. Note that the figure is not drawn to scale. G M H N 04 HN = LJ = GK =

Consider AGHJ in the figure below. The perpendicular bisectors of its sides are KN, LN, and MN. They meet at a single point N. (In other words, N is the circumcenter of AGHJ.) Suppose LN=78, GJ=94, and GN=130. Find HN, LJ, and GK. Note that the figure is not drawn to scale. G M H N 04 HN = LJ = GK =

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter6: Circles
Section6.4: Some Constructions And Inequalities For The Circle
Problem 10E
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Consider AGHJ in the figure below. The perpendicular bisectors of its sides are KN, LN, and MN. They meet at a single point N. (In other words, N is the circumcenter of AGHJ.) Suppose LN=78, GJ=94, and GN=130. Find HN, LJ, and GK. Note that the figure is not drawn to scale. M H N m K J HN I LJ = GK = X
Transcribed Image Text:Consider AGHJ in the figure below. The perpendicular bisectors of its sides are KN, LN, and MN. They meet at a single point N. (In other words, N is the circumcenter of AGHJ.) Suppose LN=78, GJ=94, and GN=130. Find HN, LJ, and GK. Note that the figure is not drawn to scale. M H N m K J HN I LJ = GK = X
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