Consider ABC in the figure below. The perpendicular bisectors of its sides are DG, EG, and FG. They meet at a single point G. (In other words, G is the circumcenter of AABC.) Suppose EG=40, AF=56, and AG=58. Find AB, BE, and CG. Note that the figure is not drawn to scale. B A G E O C AB = BE CG X

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