Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The oxygen-hydrogen distance is 0.096 nm.
Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The oxygen-hydrogen distance is 0.096 nm.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![For all following sections, assume |2|= 1 |p|= 5, R₁ = 5 mm, R₁ =
15 mm, and R₂ = 2 cm.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1e65d3f-3c77-4e7f-88fc-bf17213b1ce1%2Feb940c14-0743-4aef-a3d2-76381c3d6bdc%2F4wuy0n8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For all following sections, assume |2|= 1 |p|= 5, R₁ = 5 mm, R₁ =
15 mm, and R₂ = 2 cm.
![Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen
atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The
oxygen-hydrogen distance is 0.096 nm.
104.5"
0.096 nm
T:
Considering the atoms as non-bonded, independent charges... what is the net
electric force vector on the oxygen atom (blue)?
insidering the atoms as non-bonded, independent charges... what is the
potential energy of this arrangement?
Iculate the electric dipole moment (i.e. dipole vector) of the water molecule,
using the axes in the figure to establish unit vectors. Hint: Treat the molecule as two
independent dipoles, and add the moments as vectors.
I claim it is p = -1.88 x 10-299 Cm. Am I correct? Why is it negative?
(NOTE: The measured value of the dipole moment of water is about [p] =
0.617 x 10-29 C m, or about 1/3 of our calculated value.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1e65d3f-3c77-4e7f-88fc-bf17213b1ce1%2Feb940c14-0743-4aef-a3d2-76381c3d6bdc%2F9a8dyil_processed.png&w=3840&q=75)
Transcribed Image Text:Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen
atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The
oxygen-hydrogen distance is 0.096 nm.
104.5"
0.096 nm
T:
Considering the atoms as non-bonded, independent charges... what is the net
electric force vector on the oxygen atom (blue)?
insidering the atoms as non-bonded, independent charges... what is the
potential energy of this arrangement?
Iculate the electric dipole moment (i.e. dipole vector) of the water molecule,
using the axes in the figure to establish unit vectors. Hint: Treat the molecule as two
independent dipoles, and add the moments as vectors.
I claim it is p = -1.88 x 10-299 Cm. Am I correct? Why is it negative?
(NOTE: The measured value of the dipole moment of water is about [p] =
0.617 x 10-29 C m, or about 1/3 of our calculated value.
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