Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5º. The oxygen-hydrogen distance is 0.096 nm. Ľ L 104.5" 0.096 nm Te Considering the atoms as non-bonded, independent charges... what is the net electric force vector on the oxygen atom (blue)? insidering the atoms as non-bonded, independent charges... what is the potential energy of this arrangement? Iculate the electric dipole moment (i.e. dipole vector) of the water molecule, using the axes in the figure to establish unit vectors. Hint: Treat the molecule as two independent dipoles, and add the moments as vectors.
Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5º. The oxygen-hydrogen distance is 0.096 nm. Ľ L 104.5" 0.096 nm Te Considering the atoms as non-bonded, independent charges... what is the net electric force vector on the oxygen atom (blue)? insidering the atoms as non-bonded, independent charges... what is the potential energy of this arrangement? Iculate the electric dipole moment (i.e. dipole vector) of the water molecule, using the axes in the figure to establish unit vectors. Hint: Treat the molecule as two independent dipoles, and add the moments as vectors.
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Question
![Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen
atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The
oxygen-hydrogen distance is 0.096 nm.
104.5"
0.096 nm
T:
Considering the atoms as non-bonded, independent charges... what is the net
electric force vector on the oxygen atom (blue)?
insidering the atoms as non-bonded, independent charges... what is the
potential energy of this arrangement?
Iculate the electric dipole moment (i.e. dipole vector) of the water molecule,
using the axes in the figure to establish unit vectors. Hint: Treat the molecule as two
independent dipoles, and add the moments as vectors.
I claim it is p = -1.88 x 10-299 Cm. Am I correct? Why is it negative?
(NOTE: The measured value of the dipole moment of water is about [p] =
0.617 x 10-29 C m, or about 1/3 of our calculated value.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1e65d3f-3c77-4e7f-88fc-bf17213b1ce1%2F361f79f2-a156-4d93-9052-561b9704d9bc%2Fz0t705f_processed.png&w=3840&q=75)
Transcribed Image Text:Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen
atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The
oxygen-hydrogen distance is 0.096 nm.
104.5"
0.096 nm
T:
Considering the atoms as non-bonded, independent charges... what is the net
electric force vector on the oxygen atom (blue)?
insidering the atoms as non-bonded, independent charges... what is the
potential energy of this arrangement?
Iculate the electric dipole moment (i.e. dipole vector) of the water molecule,
using the axes in the figure to establish unit vectors. Hint: Treat the molecule as two
independent dipoles, and add the moments as vectors.
I claim it is p = -1.88 x 10-299 Cm. Am I correct? Why is it negative?
(NOTE: The measured value of the dipole moment of water is about [p] =
0.617 x 10-29 C m, or about 1/3 of our calculated value.
Expert Solution
Step 1
We have given a hydrogen atom
The charge of oxigen atom is -2e.
The charge on hydrogen atom is +e.
The bond angle is 104.5°.
Distance between the hydrogen atom and oxigen atom is 0.096nm.
We have to calculate the following things
1- Electric Force on oxigen atom.
2-Potential energy of the system.
3-Dipole moment.
Step by step
Solved in 4 steps with 3 images
