Consider a two-link network where Host A is connected to the router by a 1 Mbps link with 10 ms propagation delay and the router is connected to Host B by a 15 Mbps link with a 25 ms propagation delay. Host A sends a 1500-byte packet to Host B. What is the transmission delay (in ms) of the packet from the router to Host B?
Consider a two-link network where Host A is connected to the router by a 1 Mbps link with 10 ms propagation delay and the router is connected to Host B by a 15 Mbps link with a 25 ms propagation delay. Host A sends a 1500-byte packet to Host B. What is the transmission delay (in ms) of the packet from the router to Host B?
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![**Network Transmission Delay Calculation**
Consider a two-link network where **Host A** is connected to the router by a 1 Mbps link with a 10 ms propagation delay, and the router is connected to **Host B** by a 15 Mbps link with a 25 ms propagation delay. **Host A** sends a 1500-byte packet to **Host B**.
**Question:** What is the transmission delay (in milliseconds) of the packet from the router to **Host B**?
### Explanation:
To solve this problem, let's break it down step-by-step:
1. **Conversion of Packet Size:**
The packet size is given as 1500 bytes. Transmission delays are typically calculated in bits per second (bps). Therefore, we need to convert the packet size from bytes to bits:
\[
1500 \text{ bytes} \times 8 = 12000 \text{ bits}
\]
2. **Transmission Delay Calculation:**
Transmission delay \( t_{\text{transmission}} \) is the time it takes to push all the packet's bits into the link. It can be calculated using the formula:
\[
t_{\text{transmission}} = \frac{\text{Packet size (in bits)}}{\text{Link bandwidth (in bps)}}
\]
The link between the router and Host B has a bandwidth of 15 Mbps (15 Megabits per second or 15,000,000 bits per second). Therefore:
\[
t_{\text{transmission}} = \frac{12000 \text{ bits}}{15,000,000 \text{ bits per second}} = 0.0008 \text{ seconds}
\]
Converting seconds to milliseconds:
\[
0.0008 \text{ seconds} \times 1000 = 0.8 \text{ milliseconds}
\]
### Summary:
The transmission delay of the packet from the router to **Host B** is **0.8 milliseconds**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F55d52e12-5d83-4118-bfcc-903cc074d889%2F447cc0c5-1205-4181-b281-5a0e2e350617%2Fkz6kolr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Network Transmission Delay Calculation**
Consider a two-link network where **Host A** is connected to the router by a 1 Mbps link with a 10 ms propagation delay, and the router is connected to **Host B** by a 15 Mbps link with a 25 ms propagation delay. **Host A** sends a 1500-byte packet to **Host B**.
**Question:** What is the transmission delay (in milliseconds) of the packet from the router to **Host B**?
### Explanation:
To solve this problem, let's break it down step-by-step:
1. **Conversion of Packet Size:**
The packet size is given as 1500 bytes. Transmission delays are typically calculated in bits per second (bps). Therefore, we need to convert the packet size from bytes to bits:
\[
1500 \text{ bytes} \times 8 = 12000 \text{ bits}
\]
2. **Transmission Delay Calculation:**
Transmission delay \( t_{\text{transmission}} \) is the time it takes to push all the packet's bits into the link. It can be calculated using the formula:
\[
t_{\text{transmission}} = \frac{\text{Packet size (in bits)}}{\text{Link bandwidth (in bps)}}
\]
The link between the router and Host B has a bandwidth of 15 Mbps (15 Megabits per second or 15,000,000 bits per second). Therefore:
\[
t_{\text{transmission}} = \frac{12000 \text{ bits}}{15,000,000 \text{ bits per second}} = 0.0008 \text{ seconds}
\]
Converting seconds to milliseconds:
\[
0.0008 \text{ seconds} \times 1000 = 0.8 \text{ milliseconds}
\]
### Summary:
The transmission delay of the packet from the router to **Host B** is **0.8 milliseconds**.
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