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Consider a two-link network where Host A is connected to the router by a 1 Mbps link with 10 ms propagation delay and the router is connected to Host B by a 15 Mbps link with a 25 ms propagation delay. Host A sends a 1500-byte packet to Host B. What is the transmission delay (in ms) of the packet from the router to Host B?

Consider a two-link network where Host A is connected to the router by a 1 Mbps link with 10 ms propagation delay and the router is connected to Host B by a 15 Mbps link with a 25 ms propagation delay. Host A sends a 1500-byte packet to Host B. What is the transmission delay (in ms) of the packet from the router to Host B?

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**Network Transmission Delay Calculation** Consider a two-link network where **Host A** is connected to the router by a 1 Mbps link with a 10 ms propagation delay, and the router is connected to **Host B** by a 15 Mbps link with a 25 ms propagation delay. **Host A** sends a 1500-byte packet to **Host B**. **Question:** What is the transmission delay (in milliseconds) of the packet from the router to **Host B**? ### Explanation: To solve this problem, let's break it down step-by-step: 1. **Conversion of Packet Size:** The packet size is given as 1500 bytes. Transmission delays are typically calculated in bits per second (bps). Therefore, we need to convert the packet size from bytes to bits: \[ 1500 \text{ bytes} \times 8 = 12000 \text{ bits} \] 2. **Transmission Delay Calculation:** Transmission delay \( t_{\text{transmission}} \) is the time it takes to push all the packet's bits into the link. It can be calculated using the formula: \[ t_{\text{transmission}} = \frac{\text{Packet size (in bits)}}{\text{Link bandwidth (in bps)}} \] The link between the router and Host B has a bandwidth of 15 Mbps (15 Megabits per second or 15,000,000 bits per second). Therefore: \[ t_{\text{transmission}} = \frac{12000 \text{ bits}}{15,000,000 \text{ bits per second}} = 0.0008 \text{ seconds} \] Converting seconds to milliseconds: \[ 0.0008 \text{ seconds} \times 1000 = 0.8 \text{ milliseconds} \] ### Summary: The transmission delay of the packet from the router to **Host B** is **0.8 milliseconds**.
Transcribed Image Text:**Network Transmission Delay Calculation** Consider a two-link network where **Host A** is connected to the router by a 1 Mbps link with a 10 ms propagation delay, and the router is connected to **Host B** by a 15 Mbps link with a 25 ms propagation delay. **Host A** sends a 1500-byte packet to **Host B**. **Question:** What is the transmission delay (in milliseconds) of the packet from the router to **Host B**? ### Explanation: To solve this problem, let's break it down step-by-step: 1. **Conversion of Packet Size:** The packet size is given as 1500 bytes. Transmission delays are typically calculated in bits per second (bps). Therefore, we need to convert the packet size from bytes to bits: \[ 1500 \text{ bytes} \times 8 = 12000 \text{ bits} \] 2. **Transmission Delay Calculation:** Transmission delay \( t_{\text{transmission}} \) is the time it takes to push all the packet's bits into the link. It can be calculated using the formula: \[ t_{\text{transmission}} = \frac{\text{Packet size (in bits)}}{\text{Link bandwidth (in bps)}} \] The link between the router and Host B has a bandwidth of 15 Mbps (15 Megabits per second or 15,000,000 bits per second). Therefore: \[ t_{\text{transmission}} = \frac{12000 \text{ bits}}{15,000,000 \text{ bits per second}} = 0.0008 \text{ seconds} \] Converting seconds to milliseconds: \[ 0.0008 \text{ seconds} \times 1000 = 0.8 \text{ milliseconds} \] ### Summary: The transmission delay of the packet from the router to **Host B** is **0.8 milliseconds**.
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