Consider a titration between 100.0 mL of 0.10 M H3ASO4 and 0.10 M NaOH. a. Sketch the titration curve. b. Label the axes, the species present at each part of the curve, and the equivalence volumes. Given the Ka values: Kai = 2.4 x 10-4, Ka2 = 5.6 x 10-8, Ka3 = 3 x 10-13, calculate the pH at each of the following points: i. 50.0 mL of NaOH has been added ii. 78.0 mL of NaOH has been added iii. 100.0 mL of NaOH has been added iv. 125.0 mL of NaOH has been added 150.0 mL of NaOH has been added vi. 200.0 mL of NaOH has been added vii. 250.0 mL of NaOH has been added
Consider a titration between 100.0 mL of 0.10 M H3ASO4 and 0.10 M NaOH. a. Sketch the titration curve. b. Label the axes, the species present at each part of the curve, and the equivalence volumes. Given the Ka values: Kai = 2.4 x 10-4, Ka2 = 5.6 x 10-8, Ka3 = 3 x 10-13, calculate the pH at each of the following points: i. 50.0 mL of NaOH has been added ii. 78.0 mL of NaOH has been added iii. 100.0 mL of NaOH has been added iv. 125.0 mL of NaOH has been added 150.0 mL of NaOH has been added vi. 200.0 mL of NaOH has been added vii. 250.0 mL of NaOH has been added
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Consider a titration between 100.0 mL of 0.10 M H3ASO4 and 0.10 M NaOH.
a. Sketch the titration curve.
b.
Label the axes, the species present at each part of the curve, and the equivalence
volumes.
Given the Ka values: Ka1 = 2.4 x 10-4, Ka2 = 5.6 × 10-8, Ka3 = 3 × 10-13, calculate the pH
at each of the following points:
i. 50.0 mL of NaOH has been added
ii. 78.0 mL of NaOH has been added
iii. 100.0 mL of NaOH has been added
iv. 125.0 mL of NaOH has been added
150.0 mL of NaOH has been added
vi. 200.0 mL of NaOH has been added
vii. 250.0 mL of NaOH has been added
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