Consider a spring that does not obey Hooke's lawvery faithfully. One end of the spring is fixed. To keepthe spring stretched or compressed an amount x, aforce along the x-axis with x-componentF, = kx – b2 + cx must be applied to the freeend. Here k = 100 N/m, b = 700 N/m2, andc = 12, 000 N/m³. Note that x > 0 when thespring is stretched and x <0 when it is compressed.Part AHow much work must be done to stretch this spring by 0.050 m from its unstretched length?Express your answer in joules.nν ΑΣφW =JPart BHow much work must be done to compress this spring by 0.050 m from its unstretched length?Express your answer in joules.W =J Part CIs it easier to stretch or compress this spring?to stretchO to compress

Given : F = kx - bx2 + cz3 k = 100 N/mb = 700 N/m2c = 12,000 N/m3

Consider a spring that does not obey Hooke's law very faithfully. One end of the spring is fixed. To keep the spring stretched or compressed an amount a, a force along the x-axis with x-component F, = ka – ba? + ca must be applied to the free end. Here k = 100 N/m, b=700 N/m?, and c = 12,000 N/m. Note that z > 0 when the spring is stretched and a <0 when it is compressed.

Consider a spring that does not obey Hooke's law very faithfully. One end of the spring is fixed. To keep the spring stretched or compressed an amount a, a force along the x-axis with x-component F, = ka – ba? + ca must be applied to the free end. Here k = 100 N/m, b=700 N/m?, and c = 12,000 N/m. Note that z > 0 when the spring is stretched and a <0 when it is compressed.

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter7: Work And Kinetic Energy

Section: Chapter Questions

Problem 39P: A bungee cord is essentially a very long rubber band that can stretch up to four times its...

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Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest. 

Question

Consider a spring that does not obey Hooke's law
very faithfully. One end of the spring is fixed. To keep
the spring stretched or compressed an amount x, a
force along the x-axis with x-component
F, = kx – b2 + cx must be applied to the free
end. Here k = 100 N/m, b = 700 N/m2, and
c = 12, 000 N/m³. Note that x > 0 when the
spring is stretched and x <0 when it is compressed.
Part A
How much work must be done to stretch this spring by 0.050 m from its unstretched length?
Express your answer in joules.
nν ΑΣφ
W =
J
Part B
How much work must be done to compress this spring by 0.050 m from its unstretched length?
Express your answer in joules.
W =
J

Part C
Is it easier to stretch or compress this spring?
to stretch
O to compress

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