Consider a situation of simple harmonic motion in which the distance between the endpoints is 2.95 m and exactly 77 cycles are completed in 20.2 s. When this motion is viewed as a projection of circular motion, what is the radius, r, and angular velocity, ω, of the circular motion?

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A: Given,x = 4.1t2 + 3.1y = 3.6t3 +5.3t  =3.2 sdxdt =x'=4.1×2t dydt = y'=3.6×3×t2  dx2dt2…

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A: Since you have posted a question with multiple sub-parts, we will solve first three parts for you.…

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