Consider a single-degree-of-freedom system with the following equation of motion. m² + c²+kz=0 In free vibration, the response of the system is measured experimentally, as shown in the figure below. The equivalent spring constant is k= 15 N/m. Successive peak displacements are ₁ = 2 mm and z₂ = 1 mm. If the period of oscillation of the system is Ta=3s, determine the mass of the system. 3.3785 kg 112.6158 kg 0.1251 kg 15.6411 kg 56.0576 kg X₁ X₂

Consider a single-degree-of-freedom system with the following equation of motion. m² + c²+kz=0 In free vibration, the response of the system is measured experimentally, as shown in the figure below. The equivalent spring constant is k= 15 N/m. Successive peak displacements are ₁ = 2 mm and z₂ = 1 mm. If the period of oscillation of the system is Ta=3s, determine the mass of the system. 3.3785 kg 112.6158 kg 0.1251 kg 15.6411 kg 56.0576 kg X₁ X₂

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Free undamped vibrations

Whenever an object/system displaces in either side of its equilibrium position with the help of an external/internal means, then the object/system moves regularly or randomly on both sides of its equilibrium position. This motion is called vibration. Generally, there are three types of vibration: longitudinal vibration, transverse vibration, and torsional vibration.

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Consider a single-degree-of-freedom system with the following equation of motion.
më+c+kz=0
In free vibration, the response of the system is measured experimentally, as shown in the figure below. The equivalent spring constant is k = 15 N/m. Successive peak
displacements are #₁ = 2 mm and ₂ = 1 mm. If the period of oscillation of the system is Ta=3s, determine the mass of the system.
3.3785 kg
112.6158 kg
0.1251kg
15.6411kg
56.0576 kg
x2

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