Consider a single-degree-of-freedom system with the following equation of motion. m² + c²+kz=0 In free vibration, the response of the system is measured experimentally, as shown in the figure below. The equivalent spring constant is k= 15 N/m. Successive peak displacements are ₁ = 2 mm and z₂ = 1 mm. If the period of oscillation of the system is Ta=3s, determine the mass of the system. 3.3785 kg 112.6158 kg 0.1251 kg 15.6411 kg 56.0576 kg X₁ X₂

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Consider a single-degree-of-freedom system with the following equation of motion.
më+c+kz=0
In free vibration, the response of the system is measured experimentally, as shown in the figure below. The equivalent spring constant is k = 15 N/m. Successive peak
displacements are #₁ = 2 mm and ₂ = 1 mm. If the period of oscillation of the system is Ta=3s, determine the mass of the system.
3.3785 kg
112.6158 kg
0.1251kg
15.6411kg
56.0576 kg
x2
Transcribed Image Text:Consider a single-degree-of-freedom system with the following equation of motion. më+c+kz=0 In free vibration, the response of the system is measured experimentally, as shown in the figure below. The equivalent spring constant is k = 15 N/m. Successive peak displacements are #₁ = 2 mm and ₂ = 1 mm. If the period of oscillation of the system is Ta=3s, determine the mass of the system. 3.3785 kg 112.6158 kg 0.1251kg 15.6411kg 56.0576 kg x2
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