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Consider a reaction 4A → B + 6C in a liquid phase with a re The feed contains 0.1 mol/L of A and enters the reactor with

Consider a reaction 4A → B + 6C in a liquid phase with a re The feed contains 0.1 mol/L of A and enters the reactor with

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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1. Consider a reaction 4A → B + 6C in a liquid phase with a reaction rate of -A = (10h-¹) CA The feed contains 0.1 mol/L of A and enters the reactor with a flowrate of 1 mol/hr. a. Calculate the volume of a mixed flow reactor to reach 75% conversion b. Calculate the volume of a plug flow reactor to reach 75% conversion
Transcribed Image Text:1. Consider a reaction 4A → B + 6C in a liquid phase with a reaction rate of -A = (10h-¹) CA The feed contains 0.1 mol/L of A and enters the reactor with a flowrate of 1 mol/hr. a. Calculate the volume of a mixed flow reactor to reach 75% conversion b. Calculate the volume of a plug flow reactor to reach 75% conversion
n = 0 -TA = k n = 1 -TA = KCA n = 2 -TA = KC² any n = -TA kC KT CAO Table 5.1 Performance Equations for nth-order Kinetics and A = 0 Plug Flow or Batch CAO - CA CAO KT = ln CAO CA kTCao = = In CAO CA (n − 1)Chokr= 8.1 Integral Table = XA 1 1-XA - CA ΧΑ 1-XA C₁ 1-n A0/ - 1 = (1 - XA)¹-n – 1 pX₂ (20) (3.12) dX (1 (3.16) dX (4=(x) In 1- X (3.29) 1- X x₁²01²²x²-1-²-²₂2-1-²X dX fax-x X 1- X KT CAO dX ²14xx - ² m (1 + ex) = ln + EX KkT= KT= KT = САО - СА CAO CAO - CA CA Note: for batch reactor t = t V for Plug flow reactor t = where V is the reactor volume and v is the volumetric flowrate V FAo = vCAO Mixed Flow (Cao – CA) - ÁO - CA CA = XA XA 1 - XA XA CA0(1-XA)² ΧΑ Cho (1 − XA)" (14a) (15)
Transcribed Image Text:n = 0 -TA = k n = 1 -TA = KCA n = 2 -TA = KC² any n = -TA kC KT CAO Table 5.1 Performance Equations for nth-order Kinetics and A = 0 Plug Flow or Batch CAO - CA CAO KT = ln CAO CA kTCao = = In CAO CA (n − 1)Chokr= 8.1 Integral Table = XA 1 1-XA - CA ΧΑ 1-XA C₁ 1-n A0/ - 1 = (1 - XA)¹-n – 1 pX₂ (20) (3.12) dX (1 (3.16) dX (4=(x) In 1- X (3.29) 1- X x₁²01²²x²-1-²-²₂2-1-²X dX fax-x X 1- X KT CAO dX ²14xx - ² m (1 + ex) = ln + EX KkT= KT= KT = САО - СА CAO CAO - CA CA Note: for batch reactor t = t V for Plug flow reactor t = where V is the reactor volume and v is the volumetric flowrate V FAo = vCAO Mixed Flow (Cao – CA) - ÁO - CA CA = XA XA 1 - XA XA CA0(1-XA)² ΧΑ Cho (1 − XA)" (14a) (15)
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