Consider a random sample of size n drawn from a population with mean Hx and variance o. Show that: (a) X, is an unbiased estimator of µx. (E{Xn} = Hx or E {(Xn – µx)} = 0) (b) X = E i where I = "i, is an unbiased estimator of ux vi=1 (c) E{(X, – #x)²} = *

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1. Consider a random sample of size n drawn from a population with mean ux and
variance o. Show that:
(a) Xn is an unbiased estimator of ux. (E{Xn}= µx or E {(Xn – µx)} = 0)
-
(b) X = E i where I = E, i, is an unbiased estimator of ux
ixi
(c) E {(X, – #x)²} =
n
(d) š?
Σ--Χ.)2
is a biased estimator of o.
n
To prove or show this you will want to rewrite the expression for S2 adding and
subtracting µx:
E(X; - Hx + Hx - Xn)²
n
Rearrange this to get to the point where you are taking the expectations of known
expressions:
expectation from (a)
expectation from (c)
E{X;} = µx or E{(X; – µx)} = 0
E{(X; – Hx)²} = o%)
(e) The sample variance, S? = LisXi-Xn)* is an unbiased estimator of o?. (Use the
п-1
same approach as (d))
Transcribed Image Text:1. Consider a random sample of size n drawn from a population with mean ux and variance o. Show that: (a) Xn is an unbiased estimator of ux. (E{Xn}= µx or E {(Xn – µx)} = 0) - (b) X = E i where I = E, i, is an unbiased estimator of ux ixi (c) E {(X, – #x)²} = n (d) š? Σ--Χ.)2 is a biased estimator of o. n To prove or show this you will want to rewrite the expression for S2 adding and subtracting µx: E(X; - Hx + Hx - Xn)² n Rearrange this to get to the point where you are taking the expectations of known expressions: expectation from (a) expectation from (c) E{X;} = µx or E{(X; – µx)} = 0 E{(X; – Hx)²} = o%) (e) The sample variance, S? = LisXi-Xn)* is an unbiased estimator of o?. (Use the п-1 same approach as (d))
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