Consider a population with a mean μ=162 and standard deviation σ=72. Suppose random samples of size n=50 are selected from this population. a) What is the mean of the distribution of the sample mean? μx̅= b) What is the standard error of the mean? (2 decimal places) σx̅= In the following questions, round the standard error and z-scores to exactly 2 decimal places before determining probabilities. Report probabilities accurate to at least 3 decimal places. 2. What is the probability that a randomly selected sample mean is: a) greater than 155? b) less than 161.4? c) greater than 155 and less than 161.4? d) greater than 155 given less than 161.4? e) greater than 155 or greater than 161.4? 3. Between what values would you expect to find the middle 56% of the sample means? Round to the nearest integer. Between______and___________ . 4. Why are we able to use the normal distribution in the calculations above? Becasuse the standard error is large enough
Consider a population with a
- a) What is the mean of the distribution of the sample mean?
μx̅=
b) What is the standard error of the mean? (2 decimal places)
σx̅=
In the following questions, round the standard error and z-scores to exactly 2 decimal places before determining probabilities. Report probabilities accurate to at least 3 decimal places.
2. What is the probability that a randomly selected sample mean is:
a) greater than 155?
b) less than 161.4?
c) greater than 155 and less than 161.4?
d) greater than 155 given less than 161.4?
e) greater than 155 or greater than 161.4?
3. Between what values would you expect to find the middle 56% of the sample means? Round to the nearest integer.
Between______and___________ .
4. Why are we able to use the
- Becasuse the standard error is large enough
- Because the sample mean is large enough
- Because the
sample size is large enough - Because the original population is normal
Trending now
This is a popular solution!
Step by step
Solved in 5 steps