Consider a place where the gravity isone-fourth the gravity on Earth (g' =g/4), then the frequency of oscillationof a simple pendulum in that place, f',as compared to its frequency on earthis: A mass-spring system oscillates on africtionless horizontal surface in simpleharmonic motion with an amplitude A =0.1 m. At what position (x = ?) would thekinetic energy of the system be equalto three times its elastic potentialenergy (K = 3U)?

The period of a simple pendulum is given by, T=2πLg where, L is the length and g is the gravity.

Answered: Consider a place where the gravity is…

Consider a place where the gravity is one-fourth the gravity on Earth (g' = g/4), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is:

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

100%

Consider a place where the gravity is
one-fourth the gravity on Earth (g' =
g/4), then the frequency of oscillation
of a simple pendulum in that place, f',
as compared to its frequency on earth
is:

A mass-spring system oscillates on a
frictionless horizontal surface in simple
harmonic motion with an amplitude A =
0.1 m. At what position (x = ?) would the
kinetic energy of the system be equal
to three times its elastic potential
energy (K = 3U)?

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