Consider a place where the gravity is 4 times the gravity on Earth (g' = 4g), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is: O f = 9f O f - 4f O f = t/3 O f = 2f Of = f/2

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter16: Oscillations
Section: Chapter Questions
Problem 34PQ: Show that angular frequency of a physical pendulum phy=mgrCM/I (Eq. 16.33) equals the angular...
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O 1.5 sec
Consider a place where the gravity is 4 times the gravity on Earth (g' = 4g), then
the frequency of oscillation of a simple pendulum in that place, f', as compared
to its frequency on earth is:
O f = 9f
O r- 4f
O f = f/3
O f = 2f
O f = f/2
frictionless horizontal surface with a
Transcribed Image Text:O 1.5 sec Consider a place where the gravity is 4 times the gravity on Earth (g' = 4g), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is: O f = 9f O r- 4f O f = f/3 O f = 2f O f = f/2 frictionless horizontal surface with a
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