Consider a parallel plate capacitor. The space between the plates is filled with two slabs of linear dielectric material. Each slab has the thickness d/2, so that the distance between the plates is d. d/2 K1 K2 d/2 The dielectric constant of slab at the top is 2, the dielectric constant of slab at the bottom is 1.5. The free charge density on the top plate is +o, and at the bottom plate -o. Find the bound charge density at the bottom of the lower slab at the bottom of the upper slab at the top of the lower slab at the top of the upper slab Write o as "sigma" and division as "/ ". Remember to indicate " + or "- %3D

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Consider a parallel plate capacitor. The space between the plates is filled with two
slabs of linear dielectric material. Each slab has the thickness d/2, so that the
distance between the plates is d.
I d/2
K1
K2
d/2
The dielectric constant of slab at the top is 2, the dielectric constant of slab at the
bottom is 1.5. The free charge density on the top plate is +o, and at the bottom
ate –o.
Find the bound charge density
at the bottom of the lower slab
at the bottom of the upper slab
at the top of the lower slab
at the top of the upper slab
Write o as "sigma" and division as "/ ". Remember to indicate "+
" -".
%3D
Transcribed Image Text:Consider a parallel plate capacitor. The space between the plates is filled with two slabs of linear dielectric material. Each slab has the thickness d/2, so that the distance between the plates is d. I d/2 K1 K2 d/2 The dielectric constant of slab at the top is 2, the dielectric constant of slab at the bottom is 1.5. The free charge density on the top plate is +o, and at the bottom ate –o. Find the bound charge density at the bottom of the lower slab at the bottom of the upper slab at the top of the lower slab at the top of the upper slab Write o as "sigma" and division as "/ ". Remember to indicate "+ " -". %3D
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