Consider a normally-aspirated, four-stroke, spark-ignition, 1.8 L four-cylinder engine with a compression ratio of 10. The induction system uses a single throttle body, and the diameter of the throttle body is 42 mm. The air will enter the throttle body at P = 80 kPa and T = 290 K. The air will be throttled from the 80 kPa ambient pressure down to P₁ = 30 kPa in the intake manifold while the engine's crankshaft speed is 4200 rpm. Model the air as an ideal gas having constant specific heat, using 300 K values from Cengel's tables posted on Canvas. a) Find the temperature of the air in the intake manifold after the air is throttled from P₁ = 80 kPa to P = 30 kPa (answer: T₁ = 288.91 K). b) Find the density and mass flow rate of the air in the intake manifold (answers: P₁ = 0.3618 kg/m³ and m = 0.02533 kg/s). The volume of air in a cylinder at the start of the compression process is , which is the largest volume in a cylinder. The compression ratio, r, is the ratio of the largest volume in the cylinder to the smallest volume in the cylinder. r= V V maxr¹V ⇒V - V = V min max min max min The displacement in each cylinder of this Vmax-min=0.0018/4=.00045 m³ = x V = V(1-²¹)⇒ Vax four-cylinder engine is V ·V max min 1-¹ RPM 1 minute 2 60 seconds' intake An ideal four-stroke cylinder-piston engine behaves like constant volume-rate-of-flow device when it runs at a fixed speed. The crankshaft must make two revolutions in order for a cylinder to execute the Otto cycle. The volume rate of flow through one cylinder after the air passes through the throttle body is ₁=₂₁x² V-V max 1-r-¹ -=.00050 m³. , where is in m³/s if is in m³. The total volume rate of flow of the air through the intake manifold for this four- cylinder engine at 4200 rpm is = 4₁=4×₂ײ RPM 2 1 X== 4x0.00050x 60 min 4200 1 2 X-= 0.070 m³/s. 60
Consider a normally-aspirated, four-stroke, spark-ignition, 1.8 L four-cylinder engine with a compression ratio of 10. The induction system uses a single throttle body, and the diameter of the throttle body is 42 mm. The air will enter the throttle body at P = 80 kPa and T = 290 K. The air will be throttled from the 80 kPa ambient pressure down to P₁ = 30 kPa in the intake manifold while the engine's crankshaft speed is 4200 rpm. Model the air as an ideal gas having constant specific heat, using 300 K values from Cengel's tables posted on Canvas. a) Find the temperature of the air in the intake manifold after the air is throttled from P₁ = 80 kPa to P = 30 kPa (answer: T₁ = 288.91 K). b) Find the density and mass flow rate of the air in the intake manifold (answers: P₁ = 0.3618 kg/m³ and m = 0.02533 kg/s). The volume of air in a cylinder at the start of the compression process is , which is the largest volume in a cylinder. The compression ratio, r, is the ratio of the largest volume in the cylinder to the smallest volume in the cylinder. r= V V maxr¹V ⇒V - V = V min max min max min The displacement in each cylinder of this Vmax-min=0.0018/4=.00045 m³ = x V = V(1-²¹)⇒ Vax four-cylinder engine is V ·V max min 1-¹ RPM 1 minute 2 60 seconds' intake An ideal four-stroke cylinder-piston engine behaves like constant volume-rate-of-flow device when it runs at a fixed speed. The crankshaft must make two revolutions in order for a cylinder to execute the Otto cycle. The volume rate of flow through one cylinder after the air passes through the throttle body is ₁=₂₁x² V-V max 1-r-¹ -=.00050 m³. , where is in m³/s if is in m³. The total volume rate of flow of the air through the intake manifold for this four- cylinder engine at 4200 rpm is = 4₁=4×₂ײ RPM 2 1 X== 4x0.00050x 60 min 4200 1 2 X-= 0.070 m³/s. 60
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
![intake
The mass flow rate of the air through the engine is m = p₁V₁t where ₁ is the
density of the air in the intake manifold after it has been throttled from the ambient
pressure and temperature to P₁ = 30 kPa and T₁. The ideal gas equation of state may
be used to compute the density of the air in the intake manifold:
P₁
P₁
-x+
RT
air 1
P₁ =
Ꭱ Ꭲ
air 1
·→ m =
#
The speed of the air after it passes through the throttle body is V₁ =Vintake, where A is
A
the cross-sectional area of the throttle body. Conservation of mass requires
V2²
V²
P.V₁A = P.V₁A and the first law of thermodynamics requires + c₂T₁ = - -+c₂T₁.
2
2
intake
Conservation of mass may be used with the ideal gas equation of state to express
in terms of unknown temperature T₁:
P.V. P.V.
P.V₁A=p₂V₂A⇒
To
T
=
V² (P₁₂
To
2 P T₁
¹⇒V₂
-
PT₂
PT
|V₂ ⇒
V²
2
=
V² (P
To
1
2 P T₁
Now the first law of thermodynamics becomes a third-order polynomial in T₁ :
2
P₁
+c‚T₁ = V/_
- + c,‚T,‚ => c,‚² + ( V _ _ c, I. ] T² - (V²) (;
2
2 P
T
T² = 0
NOV](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe374e874-5461-490c-9f50-64cb80000b51%2Ffa3cb926-9466-4a7a-a5eb-5b39318eee5e%2Fsg2sp6k_processed.png&w=3840&q=75)
Transcribed Image Text:intake
The mass flow rate of the air through the engine is m = p₁V₁t where ₁ is the
density of the air in the intake manifold after it has been throttled from the ambient
pressure and temperature to P₁ = 30 kPa and T₁. The ideal gas equation of state may
be used to compute the density of the air in the intake manifold:
P₁
P₁
-x+
RT
air 1
P₁ =
Ꭱ Ꭲ
air 1
·→ m =
#
The speed of the air after it passes through the throttle body is V₁ =Vintake, where A is
A
the cross-sectional area of the throttle body. Conservation of mass requires
V2²
V²
P.V₁A = P.V₁A and the first law of thermodynamics requires + c₂T₁ = - -+c₂T₁.
2
2
intake
Conservation of mass may be used with the ideal gas equation of state to express
in terms of unknown temperature T₁:
P.V. P.V.
P.V₁A=p₂V₂A⇒
To
T
=
V² (P₁₂
To
2 P T₁
¹⇒V₂
-
PT₂
PT
|V₂ ⇒
V²
2
=
V² (P
To
1
2 P T₁
Now the first law of thermodynamics becomes a third-order polynomial in T₁ :
2
P₁
+c‚T₁ = V/_
- + c,‚T,‚ => c,‚² + ( V _ _ c, I. ] T² - (V²) (;
2
2 P
T
T² = 0
NOV

Transcribed Image Text:Consider a normally-aspirated, four-stroke, spark-ignition, 1.8 L four-cylinder engine
with a compression ratio of 10. The induction system uses a single throttle body, and
the diameter of the throttle body is 42 mm. The air will enter the throttle body at
P₁ = 80 kPa and T₁ = 290 K. The air will be throttled from the 80 kPa ambient
pressure down to P₁ = 30 kPa in the intake manifold while the engine's crankshaft
speed is 4200 rpm. Model the air as an ideal gas having constant specific heat, using
300 K values from Cengel's tables posted on Canvas.
a) Find the temperature of the air in the intake manifold after the air is throttled from
P₁ = 80 kPa to P₁ = 30 kPa (answer: T₁ = 288.91 K).
b) Find the density and mass flow rate of the air in the intake manifold (answers:
P₁ = 0.3618 kg/m³ and m = 0.02533 kg/s).
The volume of air in a cylinder at the start of the compression process is , which is
the largest volume in a cylinder. The compression ratio, r, is the ratio of the largest
volume in the cylinder to the smallest volume in the cylinder.
V
max ⇒ Vin = r²¹Vmax ⇒ Vmax - Vmin = Vmax (1-r²¹) ⇒ V
max
V
min
The displacement in each cylinder of this four-cylinder engine is
Vmax - Vin = 0.0018/4 =.00045 m³ ⇒ ¥ = Vmax
V-V
max
1-r¹
#
=
An ideal four-stroke cylinder-piston engine behaves like constant volume-rate-of-flow
device when it runs at a fixed speed. The crankshaft must make two revolutions in
order for a cylinder to execute the Otto cycle.
intake
V-V
max
1-r¹
The volume rate of flow through one cylinder after the air passes through the throttle
body is
₁₂= ₁₂x²
RPM 1 minute
2 60 seconds
=
min -=.00050 m³.
min
The total volume rate of flow of the air through the intake manifold for this four-
cylinder engine at 4200 rpm is
RPM 1
4200 1
4₁=4×₁₂× ·X
= 4x0.00050x- X- =
2 60
2 60
where is in m³/s if is in m³.
= 0.070 m³/s.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images

Recommended textbooks for you

Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press

Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON

Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education

Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press

Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON

Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education

Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY

Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning

Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY