Consider a normal population distribution with the value of a known. USE SALT (a) What is the confidence level for the interval x ± 2.880/√n? (Round your answer to one decimal place.) % (b) What is the confidence level for the interval x ± 1.450/√n? (Round your answer to one decimal place.) % (c) What value of z in the CI formula below results in a confidence level of 99.7%? (Round your answer to two decimal places.) a/2 O - Zal x + Za/2 FF) n Za/2 (d) Answer the question posed in part (c) for a confidence level of 62%. (Round your answer to two decimal places.) Za/2
Consider a normal population distribution with the value of a known. USE SALT (a) What is the confidence level for the interval x ± 2.880/√n? (Round your answer to one decimal place.) % (b) What is the confidence level for the interval x ± 1.450/√n? (Round your answer to one decimal place.) % (c) What value of z in the CI formula below results in a confidence level of 99.7%? (Round your answer to two decimal places.) a/2 O - Zal x + Za/2 FF) n Za/2 (d) Answer the question posed in part (c) for a confidence level of 62%. (Round your answer to two decimal places.) Za/2
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Q10
![### Understanding Confidence Intervals
Consider a normal population distribution with a known value of \(\sigma\).
#### Instructions:
1. **Use Salt Button:**
- Click the **Use Salt** button for additional assistance or tools.
#### Exercise Questions:
(a) **Confidence Level for Interval \( \bar{x} \pm 2.88\frac{\sigma}{\sqrt{n}} \):**
- Determine the confidence level for the interval \( \bar{x} \pm 2.88\frac{\sigma}{\sqrt{n}} \).
- Round your answer to one decimal place.
**Answer:**
\[ \_\_\_\_ \% \]
(b) **Confidence Level for Interval \( \bar{x} \pm 1.45\frac{\sigma}{\sqrt{n}} \):**
- Determine the confidence level for the interval \( \bar{x} \pm 1.45\frac{\sigma}{\sqrt{n}} \).
- Round your answer to one decimal place.
**Answer:**
\[ \_\_\_\_ \% \]
(c) **Value of \( z_{\alpha/2} \) for a Confidence Level of 99.7%:**
- What value of \( z_{\alpha/2} \) in the CI formula below results in a confidence level of 99.7%?
- Round your answer to two decimal places.
\[
\left( \bar{x} - z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}}, \bar{x} + z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}} \right)
\]
**Answer:**
\[ z_{\alpha/2} = \_\_\_\_ \]
(d) **Value of \( z_{\alpha/2} \) for a Confidence Level of 62%:**
- Answer the question posed in part (c) for a confidence level of 62%.
- Round your answer to two decimal places.
**Answer:**
\[ z_{\alpha/2} = \_\_\_\_ \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff6be9064-f0d8-4347-98bd-8b0b263612a8%2F5c49900f-7161-4568-9fdd-9b8a4d7cbc99%2Foa01qiq_processed.png&w=3840&q=75)
Transcribed Image Text:### Understanding Confidence Intervals
Consider a normal population distribution with a known value of \(\sigma\).
#### Instructions:
1. **Use Salt Button:**
- Click the **Use Salt** button for additional assistance or tools.
#### Exercise Questions:
(a) **Confidence Level for Interval \( \bar{x} \pm 2.88\frac{\sigma}{\sqrt{n}} \):**
- Determine the confidence level for the interval \( \bar{x} \pm 2.88\frac{\sigma}{\sqrt{n}} \).
- Round your answer to one decimal place.
**Answer:**
\[ \_\_\_\_ \% \]
(b) **Confidence Level for Interval \( \bar{x} \pm 1.45\frac{\sigma}{\sqrt{n}} \):**
- Determine the confidence level for the interval \( \bar{x} \pm 1.45\frac{\sigma}{\sqrt{n}} \).
- Round your answer to one decimal place.
**Answer:**
\[ \_\_\_\_ \% \]
(c) **Value of \( z_{\alpha/2} \) for a Confidence Level of 99.7%:**
- What value of \( z_{\alpha/2} \) in the CI formula below results in a confidence level of 99.7%?
- Round your answer to two decimal places.
\[
\left( \bar{x} - z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}}, \bar{x} + z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}} \right)
\]
**Answer:**
\[ z_{\alpha/2} = \_\_\_\_ \]
(d) **Value of \( z_{\alpha/2} \) for a Confidence Level of 62%:**
- Answer the question posed in part (c) for a confidence level of 62%.
- Round your answer to two decimal places.
**Answer:**
\[ z_{\alpha/2} = \_\_\_\_ \]
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