Consider a loan of $7000 with an APR of 9% and a loan term of 10 years. Complete parts (a) through (c) below. a. Use technology to construct a table showing the interest payment and loan balance after each month. Verify that, with monthly payments of $88.67, the loan balance reaches $0 after 120 months. (Do not round until the final answer. Then round to the nearest cent as needed.) Month Interest Principal Balance $7000.00 S6963 83 S52.50 S36.17 1 119 120
Consider a loan of $7000 with an APR of 9% and a loan term of 10 years. Complete parts (a) through (c) below. a. Use technology to construct a table showing the interest payment and loan balance after each month. Verify that, with monthly payments of $88.67, the loan balance reaches $0 after 120 months. (Do not round until the final answer. Then round to the nearest cent as needed.) Month Interest Principal Balance $7000.00 S6963 83 S52.50 S36.17 1 119 120
Essentials Of Investments
11th Edition
ISBN:9781260013924
Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.
Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.
Chapter1: Investments: Background And Issues
Section: Chapter Questions
Problem 1PS
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![**Loan Amortization Table Construction**
This example demonstrates how to create a loan amortization table for a loan of $7,000 with an Annual Percentage Rate (APR) of 9% and a loan term of 10 years. The objective is to verify that with monthly payments of $88.67, the loan balance will be reduced to $0 after 120 months.
*Instructions for Part (a)*
**Objective:** Use technology to construct a table showing the interest payment, principal payment, and loan balance after each month.
*Note:* Do not round until the final answer. Then, round to the nearest cent as needed.
**Loan Amortization Details:**
- **Initial Loan Amount:** $7,000
- **Monthly Payment:** $88.67
- **APR:** 9%
- **Loan Term:** 10 years (120 months)
| Month | Interest | Principal | Balance |
|-------|----------|-----------|----------|
| 0 | | | $7,000.00|
| 1 | $52.50 | $36.17 | $6,963.83|
| 2 | | | |
| ... | | | |
| 119 | | | |
| 120 | | | |
**Diagram Explanation:**
- The table is structured to show each month from the start of the loan (month 0) to the end (month 120).
- Under each month, the columns display the interest payment, principal payment, and remaining loan balance.
- The interest for the first month is calculated as $52.50, and the principal payment is $36.17, reducing the initial balance from $7,000.00 to $6,963.83.
- The process repeats, with monthly payments continuing until month 120 when the balance should reach $0.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F880da8d0-3f39-4714-825b-30fcebcbf035%2Fc432636f-14ff-44ec-bae9-967607bae560%2Fnrvbw4s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Loan Amortization Table Construction**
This example demonstrates how to create a loan amortization table for a loan of $7,000 with an Annual Percentage Rate (APR) of 9% and a loan term of 10 years. The objective is to verify that with monthly payments of $88.67, the loan balance will be reduced to $0 after 120 months.
*Instructions for Part (a)*
**Objective:** Use technology to construct a table showing the interest payment, principal payment, and loan balance after each month.
*Note:* Do not round until the final answer. Then, round to the nearest cent as needed.
**Loan Amortization Details:**
- **Initial Loan Amount:** $7,000
- **Monthly Payment:** $88.67
- **APR:** 9%
- **Loan Term:** 10 years (120 months)
| Month | Interest | Principal | Balance |
|-------|----------|-----------|----------|
| 0 | | | $7,000.00|
| 1 | $52.50 | $36.17 | $6,963.83|
| 2 | | | |
| ... | | | |
| 119 | | | |
| 120 | | | |
**Diagram Explanation:**
- The table is structured to show each month from the start of the loan (month 0) to the end (month 120).
- Under each month, the columns display the interest payment, principal payment, and remaining loan balance.
- The interest for the first month is calculated as $52.50, and the principal payment is $36.17, reducing the initial balance from $7,000.00 to $6,963.83.
- The process repeats, with monthly payments continuing until month 120 when the balance should reach $0.
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