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Consider a hash table using separate chaining with an array of size 10 and a hash function of key % 10. What would linked list at index 9 be after the following operations? For simplicity, we ignore the value. //SeparateChainingHashST SeparatechainingHashST st = new SeparateChainingHashST(); st.put (19, -); st.put (20, -); st.put (10, -); st.put (32, -); st.put (9, -); st.put (43, -); st.put (39, -); O 39,9,19 O 10,20 O null O 19,20,10,32.9,43,39

Consider a hash table using separate chaining with an array of size 10 and a hash function of key % 10. What would linked list at index 9 be after the following operations? For simplicity, we ignore the value. //SeparateChainingHashST SeparatechainingHashST st = new SeparateChainingHashST(); st.put (19, -); st.put (20, -); st.put (10, -); st.put (32, -); st.put (9, -); st.put (43, -); st.put (39, -); O 39,9,19 O 10,20 O null O 19,20,10,32.9,43,39

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Consider a hash table using separate chaining with an array of size 10 and a hash function of key % 10. What would linked list at index 9 be after the following operations? For simplicity, we ignore the value. //SeparateChainingHashST<Key, Value> SeparatechainingHashST<Integer, String> st = new SeparateChainingHashST<Integer, value> (); st.put (19, -); st.put (20, -); st.put (10, -); st.put (32, -); st.put (9, -); st.put (43, -); st.put (39, -)3; O 39,9.19 O 10,20 O null O 19,20,10,32,.9,43,39
Transcribed Image Text:Consider a hash table using separate chaining with an array of size 10 and a hash function of key % 10. What would linked list at index 9 be after the following operations? For simplicity, we ignore the value. //SeparateChainingHashST<Key, Value> SeparatechainingHashST<Integer, String> st = new SeparateChainingHashST<Integer, value> (); st.put (19, -); st.put (20, -); st.put (10, -); st.put (32, -); st.put (9, -); st.put (43, -); st.put (39, -)3; O 39,9.19 O 10,20 O null O 19,20,10,32,.9,43,39
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