Consider a function 9 q (x) = (x – 3) 2 defined for x > 3. Find the expression for the remainder term r3 (x) in the Taylor series for this function centered at æo = 6. 39.375 (x–6)³ (ã–3)1.5 r3 (x) = 3! 15.75 (x–3)³ (5–3)2.5 3! r3 (z) 39.375 (2–3)³ (ž–3)1.5 r3 (z) = 3! 15.75 (7–6)³ (5–3)2.5 3! r3 (x) = 39.375 (æ–3)³ (ã–6) 1.5 (x) T3 3! 15.75 (r–3)³ (ã–6)2.5 O r3 (2) 3! Where a has a value between x and 6.

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