Consider a flat-plate solar collector placed horizontally on the flat roof of a house. The collector is 5 ft wide and 15 ft long, and the average temperature of the exposed surface of the collector is 94°F. The emissivity of the exposed surface of the collector is 0.9. Determine the rate of heat loss from the collector by convection and radiation on a calm day when the ambient air temperature is 70 °F and the effective sky temperature for radiation exchange is 50°F. Take the convection heat transfer coefficient on the exposed surface as 2.5 Btu/h-ft2. F.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question
### Heat Loss Calculation for a Flat-Plate Solar Collector

Consider a flat-plate solar collector placed horizontally on the flat roof of a house. The collector dimensions are as follows:
- **Width**: 5 ft
- **Length**: 15 ft

The average temperature of the exposed surface of the collector is **94°F**. The emissivity of the exposed surface of the collector is **0.9**. 

#### Objective:
Determine the rate of heat loss from the collector by convection and radiation on a calm day when the ambient air temperature is **70°F** and the effective sky temperature for radiation exchange is **50°F**. 

Take the convection heat transfer coefficient on the exposed surface as **2.5 Btu/h·ft²·°F**.

#### Given:
- \(\sigma = 0.1714 \times 10^{-8} \text{ Btu/h·ft²·R}^4\)
- Solar collector surface temperature, \(T_s = 94°F\)
- Ambient air temperature, \(T_{air} = 70°F\)
- Effective sky temperature, \(T_{sky} = 50°F\)
- Convection heat transfer coefficient, \(h = 2.5 \text{ Btu/h·ft²·°F}\)
- Emissivity, \(\varepsilon = 0.9\)

#### Calculation of Heat Loss:

Using the given data, the total heat loss from the collector can be broken down into:
1. **Convective Heat Loss**: 
   \[ Q_{conv} = h \cdot A \cdot (T_s - T_{air}) \]

2. **Radiative Heat Loss**: 
   \[ Q_{rad} = \varepsilon \cdot \sigma \cdot A \cdot (T_s^4 - T_{sky}^4) \]

where:
- \(A\) is the area of the solar collector.
- \(T_s, T_{air}, T_{sky}\) are the temperatures in Rankine (°R), where \(°R = °F + 459.67\).

Given the area \(A = 5 \times 15 = 75 \text{ ft}^2\):

- \(T_s = 94 + 459.67\)
- \(T_{air} = 70 + 459.67\
Transcribed Image Text:### Heat Loss Calculation for a Flat-Plate Solar Collector Consider a flat-plate solar collector placed horizontally on the flat roof of a house. The collector dimensions are as follows: - **Width**: 5 ft - **Length**: 15 ft The average temperature of the exposed surface of the collector is **94°F**. The emissivity of the exposed surface of the collector is **0.9**. #### Objective: Determine the rate of heat loss from the collector by convection and radiation on a calm day when the ambient air temperature is **70°F** and the effective sky temperature for radiation exchange is **50°F**. Take the convection heat transfer coefficient on the exposed surface as **2.5 Btu/h·ft²·°F**. #### Given: - \(\sigma = 0.1714 \times 10^{-8} \text{ Btu/h·ft²·R}^4\) - Solar collector surface temperature, \(T_s = 94°F\) - Ambient air temperature, \(T_{air} = 70°F\) - Effective sky temperature, \(T_{sky} = 50°F\) - Convection heat transfer coefficient, \(h = 2.5 \text{ Btu/h·ft²·°F}\) - Emissivity, \(\varepsilon = 0.9\) #### Calculation of Heat Loss: Using the given data, the total heat loss from the collector can be broken down into: 1. **Convective Heat Loss**: \[ Q_{conv} = h \cdot A \cdot (T_s - T_{air}) \] 2. **Radiative Heat Loss**: \[ Q_{rad} = \varepsilon \cdot \sigma \cdot A \cdot (T_s^4 - T_{sky}^4) \] where: - \(A\) is the area of the solar collector. - \(T_s, T_{air}, T_{sky}\) are the temperatures in Rankine (°R), where \(°R = °F + 459.67\). Given the area \(A = 5 \times 15 = 75 \text{ ft}^2\): - \(T_s = 94 + 459.67\) - \(T_{air} = 70 + 459.67\
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Convection
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY