Consider a drug testing company that provides a test for marijuana usage. Among 328 tested subjects, results from 29 subjects were wrong (either a false positive or a false negative). Use a 0.01 significance level to test the claim that less than 10 percent of the test results are wrong. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p=0.1 Ha:p<0.1 O B. Ho p=0.1 H: p>0.1 O C. Ho: p<0.1 H: p=0.1 O D. Ho: p=0.1 H: p#0.1 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) >

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Consider a drug testing company that provides a test for marijuana usage. Among 328 tested subjects, results from 29 subjects were wrong (either a false positive or a false negative). Use a 0.01 significance level to test the claim that less than 10 percent of the test results are wrong.

**Identify the null and alternative hypotheses for this test. Choose the correct answer below.**

- A. \( H_0: p = 0.1 \)
      \( H_1: p < 0.1 \)
 
- B. \( H_0: p = 0.1 \)
      \( H_1: p > 0.1 \)

- C. \( H_0: p < 0.1 \)
      \( H_1: p = 0.1 \)

- D. \( H_0: p = 0.1 \)
      \( H_1: p \neq 0.1 \)

**Identify the test statistic for this hypothesis test.**

The test statistic for this hypothesis test is \(\_\_\_\_\_\).

*(Round to two decimal places as needed.)*

**Identify the P-value for this hypothesis test.**

The P-value for this hypothesis test is \(\_\_\_\_\_\).

*(Round to three decimal places as needed.)*

**Identify the conclusion for this hypothesis test.**
Transcribed Image Text:Consider a drug testing company that provides a test for marijuana usage. Among 328 tested subjects, results from 29 subjects were wrong (either a false positive or a false negative). Use a 0.01 significance level to test the claim that less than 10 percent of the test results are wrong. **Identify the null and alternative hypotheses for this test. Choose the correct answer below.** - A. \( H_0: p = 0.1 \) \( H_1: p < 0.1 \) - B. \( H_0: p = 0.1 \) \( H_1: p > 0.1 \) - C. \( H_0: p < 0.1 \) \( H_1: p = 0.1 \) - D. \( H_0: p = 0.1 \) \( H_1: p \neq 0.1 \) **Identify the test statistic for this hypothesis test.** The test statistic for this hypothesis test is \(\_\_\_\_\_\). *(Round to two decimal places as needed.)* **Identify the P-value for this hypothesis test.** The P-value for this hypothesis test is \(\_\_\_\_\_\). *(Round to three decimal places as needed.)* **Identify the conclusion for this hypothesis test.**
**Study on the Effectiveness of Garlic for Lowering Cholesterol**

In this study, 81 subjects were treated with raw garlic to assess its effectiveness in lowering LDL cholesterol levels. Measurements of LDL cholesterol (in mg/dL) were taken before and after the treatment. The changes (before minus after) in LDL cholesterol levels had a mean of 0.8 and a standard deviation of 1.71. To evaluate the claim that garlic treatment results in a mean change in LDL cholesterol greater than 0, a significance level of 0.01 is used. Assume a simple random sample was taken. Determine the effectiveness of garlic by identifying the null and alternative hypotheses, calculating the test statistic, finding the P-value, and concluding the results for the original claim.

**Hypothesis Options:**

- **A.**
  - Null Hypothesis (\( H_0 \)): \( \mu = 0 \, \text{mg/dL} \)
  - Alternative Hypothesis (\( H_1 \)): \( \mu \neq 0 \, \text{mg/dL} \)

- **B.**
  - Null Hypothesis (\( H_0 \)): \( \mu = 0 \, \text{mg/dL} \)
  - Alternative Hypothesis (\( H_1 \)): \( \mu > 0 \, \text{mg/dL} \)

- **C.**
  - Null Hypothesis (\( H_0 \)): \( \mu = 0 \, \text{mg/dL} \)
  - Alternative Hypothesis (\( H_1 \)): \( \mu < 0 \, \text{mg/dL} \)

- **D.**
  - Null Hypothesis (\( H_0 \)): \( \mu > 0 \, \text{mg/dL} \)
  - Alternative Hypothesis (\( H_1 \)): \( \mu < 0 \, \text{mg/dL} \)

**Tasks:**

1. **Determine the Test Statistic:**
   - (Round to two decimal places as needed.)

2. **Determine the P-value:**
   - (Round to three decimal places as needed.)

3. **State the Final Conclusion:**
   - Conclude whether there is evidence to support that the mean of the population changes is greater than 0.

Click to select your answer(s).
Transcribed Image Text:**Study on the Effectiveness of Garlic for Lowering Cholesterol** In this study, 81 subjects were treated with raw garlic to assess its effectiveness in lowering LDL cholesterol levels. Measurements of LDL cholesterol (in mg/dL) were taken before and after the treatment. The changes (before minus after) in LDL cholesterol levels had a mean of 0.8 and a standard deviation of 1.71. To evaluate the claim that garlic treatment results in a mean change in LDL cholesterol greater than 0, a significance level of 0.01 is used. Assume a simple random sample was taken. Determine the effectiveness of garlic by identifying the null and alternative hypotheses, calculating the test statistic, finding the P-value, and concluding the results for the original claim. **Hypothesis Options:** - **A.** - Null Hypothesis (\( H_0 \)): \( \mu = 0 \, \text{mg/dL} \) - Alternative Hypothesis (\( H_1 \)): \( \mu \neq 0 \, \text{mg/dL} \) - **B.** - Null Hypothesis (\( H_0 \)): \( \mu = 0 \, \text{mg/dL} \) - Alternative Hypothesis (\( H_1 \)): \( \mu > 0 \, \text{mg/dL} \) - **C.** - Null Hypothesis (\( H_0 \)): \( \mu = 0 \, \text{mg/dL} \) - Alternative Hypothesis (\( H_1 \)): \( \mu < 0 \, \text{mg/dL} \) - **D.** - Null Hypothesis (\( H_0 \)): \( \mu > 0 \, \text{mg/dL} \) - Alternative Hypothesis (\( H_1 \)): \( \mu < 0 \, \text{mg/dL} \) **Tasks:** 1. **Determine the Test Statistic:** - (Round to two decimal places as needed.) 2. **Determine the P-value:** - (Round to three decimal places as needed.) 3. **State the Final Conclusion:** - Conclude whether there is evidence to support that the mean of the population changes is greater than 0. Click to select your answer(s).
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