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Consider a conducting cylindrical shell as shown below. The shell has a uniform current density, and carries a total current of . The inner radius of the shell is a and the outer radius is b- 2a. Use Ampere's law to determine the magnetic field at a point halfway through the thickness of the shell (i.e. at r 1.5a). The field at r is equal to: a r b O (0.42) H0 1/2r OHO1/2nr O (0.50) H0 1/2nr O (0.25) u_0 1/2nr

Consider a conducting cylindrical shell as shown below. The shell has a uniform current density, and carries a total current of . The inner radius of the shell is a and the outer radius is b- 2a. Use Ampere's law to determine the magnetic field at a point halfway through the thickness of the shell (i.e. at r 1.5a). The field at r is equal to: a r b O (0.42) H0 1/2r OHO1/2nr O (0.50) H0 1/2nr O (0.25) u_0 1/2nr

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Consider a conducting cylindrical shell as shown below. The shell has a uniform current density, and carries a total current of I. The inner radius of the shell is a and the outer radius is b= 2a. Use Ampere's law to determine the magnetic field at a point halfway through the thickness of the shell (i.e. at r= 1.5a). The field at r is equal to: а b O (0.42) µ_0 1/2r OHO 1/2nr O (0.50) H_0 1/2nr O (0.25) HO 1/2nr
Transcribed Image Text:Consider a conducting cylindrical shell as shown below. The shell has a uniform current density, and carries a total current of I. The inner radius of the shell is a and the outer radius is b= 2a. Use Ampere's law to determine the magnetic field at a point halfway through the thickness of the shell (i.e. at r= 1.5a). The field at r is equal to: а b O (0.42) µ_0 1/2r OHO 1/2nr O (0.50) H_0 1/2nr O (0.25) HO 1/2nr
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