Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.60 x 104 N/C as shown in the figure below. 30.0 cm E 60.0° 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box. kN - m2/c (b) Calculate the electric flux through the slanted surface of the box. |kN m2/c (c) Calculate the electric flux through the entire surface of the box. KN : m2/C

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Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.60 x 104 N/C as shown in the figure below.
30.0 сm
60.0°
10.0 сm
(a) Calculate the electric flux through the vertical rectangular surface of the box.
| KN m2/c
(b) Calculate the electric flux through the slanted surface of the box.
kN - m2/C
(c) Calculate the electric flux through the entire surface of the box.
|kN - m2/C
Transcribed Image Text:Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.60 x 104 N/C as shown in the figure below. 30.0 сm 60.0° 10.0 сm (a) Calculate the electric flux through the vertical rectangular surface of the box. | KN m2/c (b) Calculate the electric flux through the slanted surface of the box. kN - m2/C (c) Calculate the electric flux through the entire surface of the box. |kN - m2/C
30.0 cm
E
A closed right triangular box with its vertical side on the left and
downward słope qp the right rests within a horizontal electric ftetd
Jeetdrgthat points from left to right. The box has a height of
10.0 dm and a depth of 30.0 cm. The downward slope of the box
makes an angle of 60 degrees with the vertical.
Transcribed Image Text:30.0 cm E A closed right triangular box with its vertical side on the left and downward słope qp the right rests within a horizontal electric ftetd Jeetdrgthat points from left to right. The box has a height of 10.0 dm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical.
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