Consider a closed rectangular box with a square base with side x and height y. a. Find an equation for the surface area of the rectangular box. S(x, y) b. If the surface area of the rectangular box is 150 dy when x = 5 feet and y = 5 dx square feet, find || feet. dy dx

Q: find dy. y = 3 csc (1 - 2√x)

A: We use the chain rule

Q: |a?V- 2 dx.

A:

Q: Find the point that is 2/5 of the distance from C to D.

A:

Q: 2 x + لوا + sech (π) = cot(y) + log2 (tanh(x))

A: Given,            ex2+2y+sechπ=coty+log2tanhxTo find : Find dydx.

Q: Given the function y=sinxcoshx. Find d3y.

A: We find dy/dx using the product rule

Q: Find dy. y = 33 + 10x4 – 5x5 dy = (Simplify your answer.)

A:

Q: Find the area of the circle whose center is at (2, -5) and tangent to the line 4x+3y-8=D0

A: Area of the circle = 9π sq.units

Q: sec2 ) 15. Evaluate. - x2 dx

A:

Q: Evaluate. Vx dx 6 76 X, dx =| 76 X (Use C as the arbitrary constant.)

A:

Q: Find dy :

A:

Q: Find the angle between y=5x2-3 and 3xy-9x2-x

A: Given y=5x2-3 --- Eq 1 and 3xy=9x2-x      --- Eq 2We know that angle between y1=k1x+b1 and y2=k2x+b2…