Consider a circuit shown below with 2 transmission gates and 2 capacitors. The values of capacitors for C₁ and C₂ are 125fF and 48fF, respectively. For the circuit, we have the following initial and final states. Vin = VDD = 3.3V At time, t<0, (x,y)=(1,0) At time t=0, the signals are changed to (x,y)=(0,1). Assume initial V₂ = 0.75V across C2. Compute the final value of voltage (V2) across C₁ and C₂ after charge sharing has taken in place. S ed. V₂=
Consider a circuit shown below with 2 transmission gates and 2 capacitors. The values of capacitors for C₁ and C₂ are 125fF and 48fF, respectively. For the circuit, we have the following initial and final states. Vin = VDD = 3.3V At time, t<0, (x,y)=(1,0) At time t=0, the signals are changed to (x,y)=(0,1). Assume initial V₂ = 0.75V across C2. Compute the final value of voltage (V2) across C₁ and C₂ after charge sharing has taken in place. S ed. V₂=
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![**Circuit Analysis with Transmission Gates and Capacitors**
Consider a circuit shown below with two transmission gates and two capacitors. The values of capacitors for \( C_1 \) and \( C_2 \) are \( 125 \, \text{fF} \) and \( 48 \, \text{fF} \), respectively. For the circuit, we have the following initial and final states:
- \( V_{\text{in}} = V_{\text{DD}} = 3.3 \, \text{V} \)
- At time, \( t < 0 \), \((x, y) = (1, 0)\)
- At time \( t = 0 \), the signals are changed to \((x, y) = (0, 1)\)
- Assume initial \( V_2 = 0.75 \, \text{V} \) across \( C_2 \).
Compute the final value of voltage (\( V_2 \)) across \( C_1 \) and \( C_2 \) after charge sharing has taken place. Show all calculations clearly.
\[ V_2 = \text{____________________________} \]
**Diagram Explanation:**
Below is a schematic representing the circuit described:
- The circuit includes two capacitors, \( C_1 \) and \( C_2 \).
- Two transmission gates, controlled by signals \( x \) and \( y \), are present.
- \( V_{\text{DD}} \) is connected to \( C_1 \), and the voltage \( V_1 \) is across \( C_1 \).
- The connection point between \( C_1 \) and \( C_2 \) changes with the activation of transmission gates, denoted by inputs \( x \) and \( y \).
This schematic illustrates the setup for evaluating charge redistribution between capacitors when the state of control signals changes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2971711f-0d6a-4a1a-bc90-d84bce58fd18%2Fbe3e1e19-732f-4753-be8d-3f25b106f667%2F649nf0w_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Circuit Analysis with Transmission Gates and Capacitors**
Consider a circuit shown below with two transmission gates and two capacitors. The values of capacitors for \( C_1 \) and \( C_2 \) are \( 125 \, \text{fF} \) and \( 48 \, \text{fF} \), respectively. For the circuit, we have the following initial and final states:
- \( V_{\text{in}} = V_{\text{DD}} = 3.3 \, \text{V} \)
- At time, \( t < 0 \), \((x, y) = (1, 0)\)
- At time \( t = 0 \), the signals are changed to \((x, y) = (0, 1)\)
- Assume initial \( V_2 = 0.75 \, \text{V} \) across \( C_2 \).
Compute the final value of voltage (\( V_2 \)) across \( C_1 \) and \( C_2 \) after charge sharing has taken place. Show all calculations clearly.
\[ V_2 = \text{____________________________} \]
**Diagram Explanation:**
Below is a schematic representing the circuit described:
- The circuit includes two capacitors, \( C_1 \) and \( C_2 \).
- Two transmission gates, controlled by signals \( x \) and \( y \), are present.
- \( V_{\text{DD}} \) is connected to \( C_1 \), and the voltage \( V_1 \) is across \( C_1 \).
- The connection point between \( C_1 \) and \( C_2 \) changes with the activation of transmission gates, denoted by inputs \( x \) and \( y \).
This schematic illustrates the setup for evaluating charge redistribution between capacitors when the state of control signals changes.
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