Consider a binary k-NN classifier where k = 4 and the two labels are “triangle" and "square". Consider classifying a new point x = 1, 1, where two of the x's nearest neighbors are labeled “triangle" and two are labeled “square" as shown below. 2 1 2 Which of the following methods can be used to break ties or avoid ties on this dataset? 1. Assign x the label of its nearest neighbor 2. Flip a coin to randomly assign a label to x (from the labels of its 4 closest points) 3. Use k =3instead 4. Use k =5instead Select one: O 1 only O 2 only O 2, 3, 4 O 2, 4 4 only O 1, 2, 3, 4 None of the above
Consider a binary k-NN classifier where k = 4 and the two labels are “triangle" and "square". Consider classifying a new point x = 1, 1, where two of the x's nearest neighbors are labeled “triangle" and two are labeled “square" as shown below. 2 1 2 Which of the following methods can be used to break ties or avoid ties on this dataset? 1. Assign x the label of its nearest neighbor 2. Flip a coin to randomly assign a label to x (from the labels of its 4 closest points) 3. Use k =3instead 4. Use k =5instead Select one: O 1 only O 2 only O 2, 3, 4 O 2, 4 4 only O 1, 2, 3, 4 None of the above
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:Consider a binary
k-NN classifier where k = 4 and the two labels are “triangle"
and "square". Consider classifying a new point x = 1, 1, where two of the x's nearest neighbors are
labeled “triangle" and two are labeled “square" as shown below.
3
2
1
3
Which of the following methods can be used to break ties or avoid ties on this dataset?
1. Assign x the label of its nearest neighbor
2. Flip a coin to randomly assign a label to x (from the labels of its 4 closest points)
3. Use k =3instead
4. Use k =5instead
Select one:
O 1 only
2 only
O 2, 3, 4
O 2, 4
4 only
O 1, 2, 3, 4
None of the above
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