Consider a binary code with 4 bits (0 or 1) in each code word. In each code word, a bit is a zero with probability 0.6, independent of any other bit.

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Consider a binary code with 4 bits (0 or 1) in each code word. In each code word, a
bit is a zero with probability 0.6, independent of any other bit.
(a) What is the probability of the code word 0101?
(b) What is the probability that a code word contains exactly two ones?

Expert Solution
Step 1

Given data:

The probability of 0 bit is P(0)=0.6.

The expression for the probability of 1 bit is,

P1=1-P0

Substitute the given values in the above expression.

P1=1-0.6=0.4

(a) 

The expression for the probability of code-word 0101 is,

Pa=P0×P1×P0×P1

Substitute the given and above-calculated values in the expression.

Pa=0.60.40.60.4=0.0576

 

Thus, the probability of code-word 0101 is 0.0576.

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