Consider a 50.0 gallon metal canister of diameter 22.0 inches fill

Given: V=50.0 gallon Diameter D= 22.0 inches Coefficient of volume expansion of waste is given by, βw=9.60*10-4(Co)-1 Initial temperature is Tin=23.0Co Final temperature is Tf=142Co Coefficient of volume expansion of metal is given by, βm=4.10*10-5(Co)-1The change in volume of the waste is given by, ∆Vw=βw*(Tf-Tin)V Plugging all given values in above equation. We get, ∆Vw=(9.60*10-4)*(142-23)50 ∆Vw=5.712 gallon..(1)The change in volume of the metal is given by ∆Vm=βm*(Tf-Tin)V Plugging all given values in above equation. We get, ∆Vm=(4.10*10-5)*(142-23)50 ∆Vm=0.24395 gallon...(2) From equation (1) and (2), So volume spilled over is given by, Vs=∆Vw-∆Vm Vs=5.712-0.24395 Vs=5.47 gallon Thus the amount of waste is 5.47 gallons.

Answered: Consider a 50.0 gallon metal canister…