Consider a 20-bit address space which is to address the following chips in the given order Chip 0: 16 KB Chip 1: 8 KB Chip 2: 8 KB Chip 3: 64 KB Chip 4: 16 KB Chip 5: 256 KB Chip 6: 128 KB Assume Chip 0 starts at address 0 and that chips are placed as close together as possible (i.e. you leave no empty addresses between chips if possible). a. The starting address of Chip 6 is K.
Consider a 20-bit address space which is to address the following chips in the given order Chip 0: 16 KB Chip 1: 8 KB Chip 2: 8 KB Chip 3: 64 KB Chip 4: 16 KB Chip 5: 256 KB Chip 6: 128 KB Assume Chip 0 starts at address 0 and that chips are placed as close together as possible (i.e. you leave no empty addresses between chips if possible). a. The starting address of Chip 6 is K.
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Can you solve this address decoding question that involves gaps please? thank you! and can you give detailed explanation?
Transcribed Image Text:Consider a 20-bit address space that addresses the following chips in the specified order:
- Chip 0: 16 KB
- Chip 1: 8 KB
- Chip 2: 8 KB
- Chip 3: 64 KB
- Chip 4: 16 KB
- Chip 5: 256 KB
- Chip 6: 128 KB
Assume Chip 0 starts at address 0 and that chips are placed as close together as possible (i.e., no empty addresses between chips if possible).
**Questions:**
a. The starting address of **Chip 6** is _____________ K.
b. Provide the following Address Line values for **Chip 4** and put an asterisk (*) by the bits which are critical. (Answers should be one of the following: 0, 1, 0\*, 1\*, or X with no space between bit and asterisk.)
- A19 = ___________
- A18 = ___________
- A17 = ___________
- A16 = ___________
- A15 = ___________
- A14 = ___________
- A13 = ___________
c. There will be a total of ___________ critical address lines for all chips.
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