Consider a 0.62kg basketball that is dropped from a height of 1 meter above the floor. 1. If the collision the basketball is completely elastic how high would the ball rise after bouncing off the ground? 2. If the ball’s collision with the ground is not completely elastic, what could you say about the maximum height that ball reaches after the bounce? 3. Calculate the change in momentum of the ball if the collision with the ground is perfectly elastic and find the average force acting on the ball during a collision of 20s duration

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A: Very basic problem from mechanics. Please have a good

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A: As per guide lines first question is answered. Kindly post the remaining as a new post. 1.a.…

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A: a) Impulse =change in momentum=mv2→-v1→=2-2i^+6j^-4i^+3j^=2-6i^+3j^=6-2i^+j^ kg-m/s

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A: Given that,m1=32 kgm2=68 kgu1=42 msu2=-17 ms

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