Consider A = (0, 5, – 1), B = (6, –1,0) and C = (-4, 0, 3). 1 (i) Find the unit vector having the same direction as 2C – A+ В. 3 (ii) Draw the vector you obtained in Part (i). (iii) Find all scalars a, b and c such that (a – 1)A – bB = cC. (iv) Solve for projĄB.
Consider A = (0, 5, – 1), B = (6, –1,0) and C = (-4, 0, 3). 1 (i) Find the unit vector having the same direction as 2C – A+ В. 3 (ii) Draw the vector you obtained in Part (i). (iii) Find all scalars a, b and c such that (a – 1)A – bB = cC. (iv) Solve for projĄB.
Related questions
Question
Hi! Please answer (iii) and (iv) with respect to the given answer.
Transcribed Image Text:0: Ginen A= 20,s,-1)
C= 2-4,0,3)
3= 2 6,-1,0)
then
2C-A +
2<-4,0,3) -
20,5,-1)++ < 6,-1,0)
<-8,0,6) - <o、四 +く2,-言0)
< -6,-16,5>
くs'
Parallel vettor to this is
K <-6,=
ー16
ノ
3<-6,-16 ,5)
= <-18, -16, 15)
ソ
-18
x'
とー-
C-18,-16 ,1S>
16
Is
ゾ
Transcribed Image Text:Consider A = (0, 5, –1), B = (6, –1,0) and C = (-4,0, 3).
1
(i) Find the unit vector having the same direction as 2C – A + =B.
3
(ii) Draw the vector you obtained in Part (i).
(ii) Find all scalars a, b and c such that (a – 1)A – bB = cC.
-
(iv) Solve for projĄB.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
