Consider 3.01*10^24 molecules of oxygen (atomic mass is 16.0 g/mole) in a container at a temperature of 22.0 degrees celsius. If this gas can be considered as an ideal gas, calculate 1.The Average translational kinetic energy of the gas. 2.The average translational kinetic energy per molecule 3. The root mean square speed of a gas molecule. 4. The most probable speed of the gas molecules.

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Consider 3.01*10^24 molecules of oxygen (atomic mass is 16.0 g/mole) in a container at a
temperature of 22.0 degrees celsius. If this gas can be considered as an ideal gas, calculate:
1.The Average translational kinetic energy of the gas.
2.The average translational kinetic energy per molecule
3. The root mean square speed of a gas molecule.
4. The most probable speed of the gas molecules.
Transcribed Image Text:Consider 3.01*10^24 molecules of oxygen (atomic mass is 16.0 g/mole) in a container at a temperature of 22.0 degrees celsius. If this gas can be considered as an ideal gas, calculate: 1.The Average translational kinetic energy of the gas. 2.The average translational kinetic energy per molecule 3. The root mean square speed of a gas molecule. 4. The most probable speed of the gas molecules.
Expert Solution
Step 1

A) The average translational kinetic energy is given by = (3/2)kT 

Where k is the Boltzman's constant.

Value of k = 1.38×10-23J.K-1.

B) The average translational kinetic energy per molecule is given by

= (3/2)kT / number of molecules

C) Root mean square speed can be calculated by (3RT/M)1/2

Where M is the molar mass in kg/mol

R is universal gas constant and T is temperature.

D) The most probable speed of the gas molecule is given by (2RT/M)1/2

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