Consider 3.0 mol of oxygen gas at 260 K and calculate the molar volume c 5 atm, 25 atm, and 60 atm using a. b. the van der Waals equation perfect gas law.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
T
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
260
Р
5
5
5
5
5
5
5
5
5
5
5
5
5
5
5
5
25
25
25
25
25
25
25
25
25
25
60
60
60
60
60
60
60
60
60
8.
a.
R
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
b.
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
8.21E-02
a
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
1.364
the van der Waals equation
b
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
3.19E-02
perfect gas law.
F
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
4.27E+00
8.55E-01
8.55E-01
8.55E-01
8.55E-01
8.55E-01
8.55E-01
8.55E-01
8.55E-01
8.55E-01
8.55E-01
3.56E-01
3.56E-01
3.56E-01
3.56E-01
3.56E-01
3.56E-01
3.56E-01
3.56E-01
3.56E-01
G
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.2728
0.0546
0.0546
0.0546
0.0546
0.0546
0.0546
0.0546
0.0546
0.0546
0.0546
0.0227
0.0227
0.0227
0.0227
0.0227
0.0227
0.0227
0.0227
0.0227
H
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
8.70E-03
1.74E-03
1.74E-03
1.74E-03
1.74E-03
1.74E-03
Consider 3.0 mol of oxygen gas at 260 K and calculate the molar volume of the gas under
5 atm, 25 atm, and 60 atm using
1.74E-03
1.74E-03
1.74F-03
1.74E-03
1.74E-03
7.25E-04
7.256-04
7.25E-04
7.25E-04
7.25E-04
7.25E-04
7.25E-04
7.25E-04
7.25E-04
Vm
4.27
4.269
4.268
4.266
4.265
4.264
4.25
4.24
4.23
4.21
4.2099
4.2091
4.20909
4.20905
4.209049
4.20904319
4.20904319
3.2
2.2
1.2
0.9
0.8
0.79
0.789
0.7889
0.78825817
0.78825817
0.5
0.3
0.29
0.291
0.2859
0.2854
0.28539
0.28535239
vdW
1.09E+00
1.08E+00
1.06E+00
1.02E+00
1.00E+00
9.84E-01
7.29E-01
5.48E-01
3.69E-01
1.67E-02
1.50E-02
9.91E-04
8.17E-04
1.19E-04
1.02E-04
1.52E-07
5.97E+01
2.42E+01
6.63E+00
5.61E-01
8.41E-02
6.92E-03
1.00E-03
4.25E-04
3.67E-04
9.39E-09
2.86E-01
4.66E-02
1.04E-03
3.07E-04
0.000376311
3.50797E-05
3.04296E-06
2.40478E-06
5.48052E-09
Transcribed Image Text:T 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 260 Р 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 25 25 25 25 25 25 25 25 25 25 60 60 60 60 60 60 60 60 60 8. a. R 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 b. 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 8.21E-02 a 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 1.364 the van der Waals equation b 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 3.19E-02 perfect gas law. F 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 4.27E+00 8.55E-01 8.55E-01 8.55E-01 8.55E-01 8.55E-01 8.55E-01 8.55E-01 8.55E-01 8.55E-01 8.55E-01 3.56E-01 3.56E-01 3.56E-01 3.56E-01 3.56E-01 3.56E-01 3.56E-01 3.56E-01 3.56E-01 G 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.2728 0.0546 0.0546 0.0546 0.0546 0.0546 0.0546 0.0546 0.0546 0.0546 0.0546 0.0227 0.0227 0.0227 0.0227 0.0227 0.0227 0.0227 0.0227 0.0227 H 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 8.70E-03 1.74E-03 1.74E-03 1.74E-03 1.74E-03 1.74E-03 Consider 3.0 mol of oxygen gas at 260 K and calculate the molar volume of the gas under 5 atm, 25 atm, and 60 atm using 1.74E-03 1.74E-03 1.74F-03 1.74E-03 1.74E-03 7.25E-04 7.256-04 7.25E-04 7.25E-04 7.25E-04 7.25E-04 7.25E-04 7.25E-04 7.25E-04 Vm 4.27 4.269 4.268 4.266 4.265 4.264 4.25 4.24 4.23 4.21 4.2099 4.2091 4.20909 4.20905 4.209049 4.20904319 4.20904319 3.2 2.2 1.2 0.9 0.8 0.79 0.789 0.7889 0.78825817 0.78825817 0.5 0.3 0.29 0.291 0.2859 0.2854 0.28539 0.28535239 vdW 1.09E+00 1.08E+00 1.06E+00 1.02E+00 1.00E+00 9.84E-01 7.29E-01 5.48E-01 3.69E-01 1.67E-02 1.50E-02 9.91E-04 8.17E-04 1.19E-04 1.02E-04 1.52E-07 5.97E+01 2.42E+01 6.63E+00 5.61E-01 8.41E-02 6.92E-03 1.00E-03 4.25E-04 3.67E-04 9.39E-09 2.86E-01 4.66E-02 1.04E-03 3.07E-04 0.000376311 3.50797E-05 3.04296E-06 2.40478E-06 5.48052E-09
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