connected subspace of a

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.2: Linear Independence, Basis, And Dimension
Problem 15EQ
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Prove Corollary with all details ( use Topology discrete)
Theorem 5.4: If Y is a connected subspace of a space X, then Ÿ is connected.
Proof: Suppose Y is connected. For a change of pace, the connectedness of Ỹ will
be shown by proving that there is no continuous function from Ÿ onto a discrete two-
point space.
Consider a continuous function f: Ÿ → {a, b} from Ÿ into such a discrete
space. We must show that f is not surjective. The restriction f | y cannot be surjective.
This means that f maps Y to only one point of {a, b}, say a:
KY) = {a}.
%3D
Since f is continuous, Theorem 4.11 guarantees that
KỸ) CRY) = {ā} = {a},
so f is not surjective. Thus, by Theorem 5.1, Ý is connected.
5.2 / Theorems on Connectedness
137
An examination of the preceding proof will reveal that Theorem 5.4 can be
strengthened as follows:
Corollary: Let Y be a connected subspace of a space X and Z a subspace of X
such that Y C ZCỸ. Then Z is connected.
Transcribed Image Text:Theorem 5.4: If Y is a connected subspace of a space X, then Ÿ is connected. Proof: Suppose Y is connected. For a change of pace, the connectedness of Ỹ will be shown by proving that there is no continuous function from Ÿ onto a discrete two- point space. Consider a continuous function f: Ÿ → {a, b} from Ÿ into such a discrete space. We must show that f is not surjective. The restriction f | y cannot be surjective. This means that f maps Y to only one point of {a, b}, say a: KY) = {a}. %3D Since f is continuous, Theorem 4.11 guarantees that KỸ) CRY) = {ā} = {a}, so f is not surjective. Thus, by Theorem 5.1, Ý is connected. 5.2 / Theorems on Connectedness 137 An examination of the preceding proof will reveal that Theorem 5.4 can be strengthened as follows: Corollary: Let Y be a connected subspace of a space X and Z a subspace of X such that Y C ZCỸ. Then Z is connected.
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