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A KEA = KEB B C = VB= J a) From the information given, calculate each of the following. /v J Yi m/s PEA = D ymax b) Determine each of the following. Some will be in terms of variables PEB = Xf c) Use conservation of energy to calculate VB. ^ J 1. Starting from rest, a skier, m = 75 kg, travels down a slope, which turns up at the bottom, launching the skier at an angle = 53 above the horizontal. Heights: h=85 m, hg = 0 m hc. =10 m. The end of the ski ramp is y = 10 m above the ground. J EA = EB = J

A KEA = KEB B C = VB= J a) From the information given, calculate each of the following. /v J Yi m/s PEA = D ymax b) Determine each of the following. Some will be in terms of variables PEB = Xf c) Use conservation of energy to calculate VB. ^ J 1. Starting from rest, a skier, m = 75 kg, travels down a slope, which turns up at the bottom, launching the skier at an angle = 53 above the horizontal. Heights: h=85 m, hg = 0 m hc. =10 m. The end of the ski ramp is y = 10 m above the ground. J EA = EB = J

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A KEA = KEB B VB= a) From the information given, calculate each of the following. J KEC = VC /vi Yi m/s b) Determine each of the following. Some will be in terms of variables J PEB = PEA = Use conservation of energy to calculate VB. J D m/s ymax Xf PEC = d) Determine each of the following. Some will be in terms of variables. e) Use conservation of energy to calculate vc. 1. Starting from rest, a skier, m = 75 kg, travels down a slope, which turns up at the bottom, launching the skier at an angle = 53 above the horizontal. Heights: h=85 m, bg = 0 m hc= 10 m. The end of the ski ramp is y₁ = 10 m above the ground. J EA = J EB = NAME J Ec=
Transcribed Image Text:A KEA = KEB B VB= a) From the information given, calculate each of the following. J KEC = VC /vi Yi m/s b) Determine each of the following. Some will be in terms of variables J PEB = PEA = Use conservation of energy to calculate VB. J D m/s ymax Xf PEC = d) Determine each of the following. Some will be in terms of variables. e) Use conservation of energy to calculate vc. 1. Starting from rest, a skier, m = 75 kg, travels down a slope, which turns up at the bottom, launching the skier at an angle = 53 above the horizontal. Heights: h=85 m, bg = 0 m hc= 10 m. The end of the ski ramp is y₁ = 10 m above the ground. J EA = J EB = NAME J Ec=
A Vix = VDx KED = C B Ty When the skier leaves the ramp at C, for v₁ use your number for vc. f) What are the (x,y) components of v₁. At ymax, determine the (x,y) components of vp. (clues) Ymax = hp m/s = my/s J D PED ymax Xf m g) Determine each of the following. Some will be in terms of variables. Viy = h) Use conservation of energy to calculate ymax, or hp. VDY 1. Starting from rest, a skier, m = 75 kg, travels down a slope, which turns up at the bottom, launching the skier at an angle = 53° above the horizontal. Heights: hA 85 m, hg = 0 m = hc = 10 m. The end of the ski ramp is Yi 10 m above the ground. J m/s ED m/s =
Transcribed Image Text:A Vix = VDx KED = C B Ty When the skier leaves the ramp at C, for v₁ use your number for vc. f) What are the (x,y) components of v₁. At ymax, determine the (x,y) components of vp. (clues) Ymax = hp m/s = my/s J D PED ymax Xf m g) Determine each of the following. Some will be in terms of variables. Viy = h) Use conservation of energy to calculate ymax, or hp. VDY 1. Starting from rest, a skier, m = 75 kg, travels down a slope, which turns up at the bottom, launching the skier at an angle = 53° above the horizontal. Heights: hA 85 m, hg = 0 m = hc = 10 m. The end of the ski ramp is Yi 10 m above the ground. J m/s ED m/s =
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