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Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Consider below EMPLOYEE table as the source data CREATE TABLE EMPLOYEE ( EMPLOYEE_ID NUMBER(6,0), NAME VARCHAR2 ( 20), SALARY NUMBER(8,2) ): INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (100, 'Jennifer',4400); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (100, 'Jennifer',4400); INSERT INTO EMPLOYEE ( EMPLOYEE_ID, NAME, SALARY) VALUES (101, 'Michael',13000); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (101, 'Michael',13000); INSERT INTO EMPLOYEE (EMPLOYEE_ID,NAME, SALARY) VALUES (101, 'Michael',13000); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (102, 'Pat',6000); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (102, 'Pat',6000); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (103, 'Den', 11000); SELECT FROM EMPLOYEE; EMPLOYEE_ID NAME SALARY 100 Jennitor 4400 100 Jervifer 4400 101 Michael 13000 101 Michael 13000 101 Michael 13000 102 Pat 6000 102 Pat 6000 103 Den 11000
Transcribed Image Text:Consider below EMPLOYEE table as the source data CREATE TABLE EMPLOYEE ( EMPLOYEE_ID NUMBER(6,0), NAME VARCHAR2 ( 20), SALARY NUMBER(8,2) ): INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (100, 'Jennifer',4400); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (100, 'Jennifer',4400); INSERT INTO EMPLOYEE ( EMPLOYEE_ID, NAME, SALARY) VALUES (101, 'Michael',13000); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (101, 'Michael',13000); INSERT INTO EMPLOYEE (EMPLOYEE_ID,NAME, SALARY) VALUES (101, 'Michael',13000); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (102, 'Pat',6000); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (102, 'Pat',6000); INSERT INTO EMPLOYEE (EMPLOYEE_ID, NAME, SALARY) VALUES (103, 'Den', 11000); SELECT FROM EMPLOYEE; EMPLOYEE_ID NAME SALARY 100 Jennitor 4400 100 Jervifer 4400 101 Michael 13000 101 Michael 13000 101 Michael 13000 102 Pat 6000 102 Pat 6000 103 Den 11000
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