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College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter9: Sequences, Probability And Counting Theory
Section9.6: Binomial Theorem
Problem 3SE: What is the Binomial Theorem and what is its use?
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**Question 10**

Compute \( \binom{5}{2} \)

**Explanation:**

The expression \( \binom{5}{2} \) represents a binomial coefficient, also known as "5 choose 2," which is used in combinatorics to determine the number of ways to choose 2 elements from a set of 5 elements without regard to the order of selection.

The formula to compute \( \binom{n}{k} \) is:

\[
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\]

In this case:

- \( n = 5 \)
- \( k = 2 \)

Therefore:

\[
\binom{5}{2} = \frac{5!}{2!(5-2)!} = \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!} = \frac{20}{2} = 10
\]

So, there are 10 ways to choose 2 elements from a set of 5 elements.
Transcribed Image Text:**Question 10** Compute \( \binom{5}{2} \) **Explanation:** The expression \( \binom{5}{2} \) represents a binomial coefficient, also known as "5 choose 2," which is used in combinatorics to determine the number of ways to choose 2 elements from a set of 5 elements without regard to the order of selection. The formula to compute \( \binom{n}{k} \) is: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] In this case: - \( n = 5 \) - \( k = 2 \) Therefore: \[ \binom{5}{2} = \frac{5!}{2!(5-2)!} = \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!} = \frac{20}{2} = 10 \] So, there are 10 ways to choose 2 elements from a set of 5 elements.
Expert Solution
Step 1

We have in general the formula for combination as,

rn = n!r!(n-r)!

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