Compute y' and y". The symbols C₁ and C₂ represent constants. y = C₁e* + C₂xex y'(x) = y"(x) = Combine these derivatives with y as a linear second-order differential equation that is free of the symbols C₁ and C₂ and has the form F(y, y', y") = 0. (Use yp fo = 0

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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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### Derivatives of a Given Function

To solve the following differential equations for educational purposes, please follow along with the steps outlined below.

**Given Function:**

\[ y = C_1 e^x + C_2 x e^x \]

where \( C_1 \) and \( C_2 \) represent constants.

**First Derivative:**

To find the first derivative, \( y'(x) \):

\[ y'(x) = \frac{d}{dx} \left(C_1 e^x + C_2 x e^x\right) \]

Using the product rule and the derivative of \( e^x \):

\[ y'(x) = C_1 e^x + C_2 \left(e^x + x e^x\right) \]

\[ y'(x) = C_1 e^x + C_2 e^x + C_2 x e^x \]

\[ y'(x) = (C_1 + C_2) e^x + C_2 x e^x \]

**Second Derivative:**

To find the second derivative, \( y''(x) \):

\[ y''(x) = \frac{d}{dx} \left( (C_1 + C_2) e^x + C_2 x e^x \right) \]

Using the product rule again:

\[ y''(x) = (C_1 + C_2) e^x + C_2 \left(e^x + x e^x\right) \]

\[ y''(x) = (C_1 + C_2) e^x + C_2 e^x + C_2 x e^x \]

\[ y''(x) = (C_1 + 2C_2) e^x + C_2 x e^x \]

**Combining Derivatives into a Linear Second-Order Differential Equation:**

We need to combine these derivatives with \( y \) as a linear second-order differential equation that is free of the symbols \( C_1 \) and \( C_2 \) and has the form \( F(y, y', y'') = 0 \):

\[ y'' - 2y' + y = 0 \]

This step ensures the resulting equation is homogeneous and does not include the constants \( C_1 \
Transcribed Image Text:### Derivatives of a Given Function To solve the following differential equations for educational purposes, please follow along with the steps outlined below. **Given Function:** \[ y = C_1 e^x + C_2 x e^x \] where \( C_1 \) and \( C_2 \) represent constants. **First Derivative:** To find the first derivative, \( y'(x) \): \[ y'(x) = \frac{d}{dx} \left(C_1 e^x + C_2 x e^x\right) \] Using the product rule and the derivative of \( e^x \): \[ y'(x) = C_1 e^x + C_2 \left(e^x + x e^x\right) \] \[ y'(x) = C_1 e^x + C_2 e^x + C_2 x e^x \] \[ y'(x) = (C_1 + C_2) e^x + C_2 x e^x \] **Second Derivative:** To find the second derivative, \( y''(x) \): \[ y''(x) = \frac{d}{dx} \left( (C_1 + C_2) e^x + C_2 x e^x \right) \] Using the product rule again: \[ y''(x) = (C_1 + C_2) e^x + C_2 \left(e^x + x e^x\right) \] \[ y''(x) = (C_1 + C_2) e^x + C_2 e^x + C_2 x e^x \] \[ y''(x) = (C_1 + 2C_2) e^x + C_2 x e^x \] **Combining Derivatives into a Linear Second-Order Differential Equation:** We need to combine these derivatives with \( y \) as a linear second-order differential equation that is free of the symbols \( C_1 \) and \( C_2 \) and has the form \( F(y, y', y'') = 0 \): \[ y'' - 2y' + y = 0 \] This step ensures the resulting equation is homogeneous and does not include the constants \( C_1 \
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