Compute u + v and u - 2v. - 5 u = - 2 , v = 1 4

icon
Related questions
Question
### Vector Operations

#### Problem Statement:
**Compute** \( \mathbf{u} + \mathbf{v} \) **and** \( \mathbf{u} - 2\mathbf{v} \).

#### Given Vectors:
\[
\mathbf{u} = \begin{bmatrix}
-5 \\
1 
\end{bmatrix}, \ \mathbf{v} = \begin{bmatrix}
-2 \\
4
\end{bmatrix}
\]

#### Calculation:
**Step 1:** Perform the addition \( \mathbf{u} + \mathbf{v} \).

\[
\mathbf{u} + \mathbf{v} = \begin{bmatrix}
-5 \\
1
\end{bmatrix} + \begin{bmatrix}
-2 \\
4
\end{bmatrix}
\]

You add each corresponding component:

\[
= \begin{bmatrix}
-5 + (-2) \\
1 + 4
\end{bmatrix}
= \begin{bmatrix}
-7 \\
5
\end{bmatrix}
\]

**Step 2:** Perform the subtraction \( \mathbf{u} - 2\mathbf{v} \).

First, calculate \( 2\mathbf{v} \):

\[
2\mathbf{v} = 2 \begin{bmatrix}
-2 \\
4
\end{bmatrix}
= \begin{bmatrix}
2 \cdot (-2) \\
2 \cdot 4
\end{bmatrix}
= \begin{bmatrix}
-4 \\
8
\end{bmatrix}
\]

Next, subtract \( 2\mathbf{v} \) from \( \mathbf{u} \):

\[
\mathbf{u} - 2\mathbf{v} = \begin{bmatrix}
-5 \\
1
\end{bmatrix} - \begin{bmatrix}
-4 \\
8
\end{bmatrix}
\]

Subtract each corresponding component:

\[
= \begin{bmatrix}
-5 - (-4) \\
1 - 8
\end{bmatrix}
= \begin{bmatrix}
-5 + 4 \\
1 - 8
\end{bmatrix}
= \begin{bmatrix}
-1 \\
-7
Transcribed Image Text:### Vector Operations #### Problem Statement: **Compute** \( \mathbf{u} + \mathbf{v} \) **and** \( \mathbf{u} - 2\mathbf{v} \). #### Given Vectors: \[ \mathbf{u} = \begin{bmatrix} -5 \\ 1 \end{bmatrix}, \ \mathbf{v} = \begin{bmatrix} -2 \\ 4 \end{bmatrix} \] #### Calculation: **Step 1:** Perform the addition \( \mathbf{u} + \mathbf{v} \). \[ \mathbf{u} + \mathbf{v} = \begin{bmatrix} -5 \\ 1 \end{bmatrix} + \begin{bmatrix} -2 \\ 4 \end{bmatrix} \] You add each corresponding component: \[ = \begin{bmatrix} -5 + (-2) \\ 1 + 4 \end{bmatrix} = \begin{bmatrix} -7 \\ 5 \end{bmatrix} \] **Step 2:** Perform the subtraction \( \mathbf{u} - 2\mathbf{v} \). First, calculate \( 2\mathbf{v} \): \[ 2\mathbf{v} = 2 \begin{bmatrix} -2 \\ 4 \end{bmatrix} = \begin{bmatrix} 2 \cdot (-2) \\ 2 \cdot 4 \end{bmatrix} = \begin{bmatrix} -4 \\ 8 \end{bmatrix} \] Next, subtract \( 2\mathbf{v} \) from \( \mathbf{u} \): \[ \mathbf{u} - 2\mathbf{v} = \begin{bmatrix} -5 \\ 1 \end{bmatrix} - \begin{bmatrix} -4 \\ 8 \end{bmatrix} \] Subtract each corresponding component: \[ = \begin{bmatrix} -5 - (-4) \\ 1 - 8 \end{bmatrix} = \begin{bmatrix} -5 + 4 \\ 1 - 8 \end{bmatrix} = \begin{bmatrix} -1 \\ -7
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Dot Products
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.