Compute the vapor pressure of an ideal solution containing 92.1 g of glycerin, C3H5(OH)3, and 184.4 g of ethanol, C2H5OH, at 40 °C. The vapor pressure of pure ethanol is 0.178 atm at 40 °C. Glycerin is essentially nonvolatile at this temperature.
Compute the vapor pressure of an ideal solution containing 92.1 g of glycerin, C3H5(OH)3, and 184.4 g of ethanol, C2H5OH, at 40 °C. The vapor pressure of pure ethanol is 0.178 atm at 40 °C. Glycerin is essentially nonvolatile at this temperature.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Vapor Pressure Lowering
Vapor pressure is the pressure exerted by a vapor
that is in dynamic equilibrium with its liquid in a closed
system.
A solution that contains a solute that is nonvolatile (not
easily vaporized) always has a lower vapor pressure than
the pure solvent.
The vapor pressure of an ideal solution is described by
Raoult's law. Each component in a solution exerts a
pressure that is equal to its mole fraction times the vapor
pressure of the pure component.
PA = X4 x P.
PA – vapor pressure exerted by component A in the solution
XẠ – mole fraction of component A
PÅ – vapor pressure of the pure substance A](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc2e8b864-3675-4e1b-a049-55ffe34aa1b7%2F0b150e8c-548c-400f-8d57-9271328c68ad%2F1tbtid_processed.png&w=3840&q=75)
Transcribed Image Text:Vapor Pressure Lowering
Vapor pressure is the pressure exerted by a vapor
that is in dynamic equilibrium with its liquid in a closed
system.
A solution that contains a solute that is nonvolatile (not
easily vaporized) always has a lower vapor pressure than
the pure solvent.
The vapor pressure of an ideal solution is described by
Raoult's law. Each component in a solution exerts a
pressure that is equal to its mole fraction times the vapor
pressure of the pure component.
PA = X4 x P.
PA – vapor pressure exerted by component A in the solution
XẠ – mole fraction of component A
PÅ – vapor pressure of the pure substance A
![7. Compute the vapor pressure
C3H5(OH)3, and 184.4 g of ethanol, C2H5OH, at 40 °C. The vapor pressure of
pure ethanol is 0.178 atm at 40 °C. Glycerin is essentially nonvolatile at this
temperature.
an ideal solution containing 92.1 g of glycerin,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc2e8b864-3675-4e1b-a049-55ffe34aa1b7%2F0b150e8c-548c-400f-8d57-9271328c68ad%2Fb5s24tw_processed.png&w=3840&q=75)
Transcribed Image Text:7. Compute the vapor pressure
C3H5(OH)3, and 184.4 g of ethanol, C2H5OH, at 40 °C. The vapor pressure of
pure ethanol is 0.178 atm at 40 °C. Glycerin is essentially nonvolatile at this
temperature.
an ideal solution containing 92.1 g of glycerin,
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