Compute the subnet mask, subnet address, broadcast address and the IP host ranges of 192.168.3.55/24 and then 192.168.70.134/29 EXPLAIN how you find your answer. 1-

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A: 1)IP 128.64.11.192/24

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A: 1. Given that, Ip address= 10.56.161.181 Subnet mask= 255.255.255.248

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Q: 1- Compute the subnet mask, subnet address, broadcast address and the IP host ranges of…

A: Given IP Address 192.168.3.55/24 in above address 24 means number of network bits is 24 and number…