Problem 2 To compare the mean cholesterol content (in milligrams) of grilled chicken sandwiches from Arby's and McDonald's, you randomly select several sandwiches from each restaurant and measure their cholesterol contents. Assume unequal population variances and assume cholesterol contents are normally distributed. The results are listed below: Arby's n₁ = 15 McDonald's n₂ = 12 x₁ = 60 mg x₂ = 70 mg s₁ = 3.59 mg S₂ = 2.41 mg (a) Construct a 95% confidence interval for the difference in mean cholesterol content of grilled chicken. (b) Are the mean cholesterol contents in Arby's and McDonald's grilled chicken sandwiches significantly different? Ise 5% level of significance

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Problem 2
To compare the mean cholesterol content (in milligrams) of grilled chicken sandwiches
from Arby's and McDonald's, you randomly select several sandwiches from each
restaurant and measure their cholesterol contents. Assume unequal population variances
and assume cholesterol contents are normally distributed. The results are listed below:
Arby's
McDonald's
n₁ = 15
n₂ = 12
x₁ = 60 mg
s₁ = 3.59 mg
x₂ = 70 mg
X.
$₂ = 2.41 mg
$2
(a) Construct a 95% confidence interval for the difference in mean cholesterol
content of grilled chicken.
(b) Are the mean cholesterol contents in Arby's and McDonald's grilled chicken
sandwiches significantly different? Use 5% level of significance.
Transcribed Image Text:Problem 2 To compare the mean cholesterol content (in milligrams) of grilled chicken sandwiches from Arby's and McDonald's, you randomly select several sandwiches from each restaurant and measure their cholesterol contents. Assume unequal population variances and assume cholesterol contents are normally distributed. The results are listed below: Arby's McDonald's n₁ = 15 n₂ = 12 x₁ = 60 mg s₁ = 3.59 mg x₂ = 70 mg X. $₂ = 2.41 mg $2 (a) Construct a 95% confidence interval for the difference in mean cholesterol content of grilled chicken. (b) Are the mean cholesterol contents in Arby's and McDonald's grilled chicken sandwiches significantly different? Use 5% level of significance.
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Compute the point estimate for the difference between the means.

Report the standard error of the difference between the sample means. Round the three decimals.

Report the margin of error. Round to three decimals.

 

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