Compute the least common multiple (LCM) of 1980 and 4200 using transform and conquer. Use the guide below: Problem Reduction Problem 1 To be solved Problem 1: LCM Icm (24, 60) = (2*2*3)*2*5 = 120 Notice that 24*60 (2*2*3)²*2*5 Problem 2 Solvable by Algo A Algo A Solution to Problem 2 = (2*2*2*3)* (2*2*3*5) = (2*2*3)² *2*5 = (2*2*3)* (2*2*3)* 2*5 = 12 * 10 12 (2*2*3)² *2*5 = 12 * 120 So, m*n = gcd(m, n) * Icm(m, n)

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Compute the least common multiple (LCM) of 1980 and 4200 using
transform and conquer. Use the guide below:
Problem Reduction
Problem 1
To be solved
Problem 1: LCM
Icm (24, 60) = (2*2*3)*2*5 = 120
Notice that
24*60
Algo A
Problem 2
Solvable by Algo A
(2*2*3)²*2*5
Solution to
Problem 2
= (2*2*2*3)* (2*2*3*5) = (2*2*3)² *2*5
= (2*2*3)* (2*2*3)* 2*5
12
* 10
(2*2*3)² *2*5 = 12 *
=
12
120
So,
m*n = gcd(m, n) * Icm(m, n)
Transcribed Image Text:Compute the least common multiple (LCM) of 1980 and 4200 using transform and conquer. Use the guide below: Problem Reduction Problem 1 To be solved Problem 1: LCM Icm (24, 60) = (2*2*3)*2*5 = 120 Notice that 24*60 Algo A Problem 2 Solvable by Algo A (2*2*3)²*2*5 Solution to Problem 2 = (2*2*2*3)* (2*2*3*5) = (2*2*3)² *2*5 = (2*2*3)* (2*2*3)* 2*5 12 * 10 (2*2*3)² *2*5 = 12 * = 12 120 So, m*n = gcd(m, n) * Icm(m, n)
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