Compute the integral with respect to x. v = 2 [3/-265) $1₁ = 2 [ ³ - * - * 1¹₁ Apply the limit value for x and obtain the volume of the solid as follows. V=2(30)-2 (³----²-(²) -뽕 -뿍) 10 = 2(2--+--3) = 2 ( /-/-/-) 16 15 = Thus, the volume of the given solid is 16. 15'

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Hello! I had difficulty solving the final answer based on the formulas given in the image i provided, for reference this is from Calculus 3 Chapter 15.2 #36, i guess the math for me doesnt seem to add up to the answer provided. Thank you in advance!

Compute the integral with respect to x.
2(5)
V=2[* - - ₁
25-1₁
= 2 [ ³ - 6 - ³ 1 ¹₁
Apply the limit value for x and obtain the volume of the solid as follows.
3(1) (1)5
(-1)³
(-1)
V = 2 ( 30) - - ²) - 2 (³-D) – (D³ - (D³)
2
10
10
=
--3)
2(2--+-
= 2 ( /-/-/-/-)
16
15
=
16
Thus, the volume of the given solid is
15'
Transcribed Image Text:Compute the integral with respect to x. 2(5) V=2[* - - ₁ 25-1₁ = 2 [ ³ - 6 - ³ 1 ¹₁ Apply the limit value for x and obtain the volume of the solid as follows. 3(1) (1)5 (-1)³ (-1) V = 2 ( 30) - - ²) - 2 (³-D) – (D³ - (D³) 2 10 10 = --3) 2(2--+- = 2 ( /-/-/-/-) 16 15 = 16 Thus, the volume of the given solid is 15'
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