Compute the indicated derivative using the chain rule. dy dx dy dx x = 1 + 3t, y = -7t; Need Help? Read It
Compute the indicated derivative using the chain rule. dy dx dy dx x = 1 + 3t, y = -7t; Need Help? Read It
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:**Compute the Indicated Derivative Using the Chain Rule**
Given:
- \( x = 1 + 3t \)
- \( y = -7t \)
Find:
- \(\frac{dy}{dx}\)
**Solution:**
You are prompted to compute \(\frac{dy}{dx}\) using the relationships provided for \(x\) and \(y\) as functions of \(t\).
**Steps:**
1. Compute \(\frac{dx}{dt}\).
- \(\frac{dx}{dt} = \frac{d}{dt}(1 + 3t) = 3\)
2. Compute \(\frac{dy}{dt}\).
- \(\frac{dy}{dt} = \frac{d}{dt}(-7t) = -7\)
3. Apply the chain rule to find \(\frac{dy}{dx}\):
- \(\frac{dy}{dx} = \frac{dy}{dt} \times \frac{dt}{dx}\)
- Since \(\frac{dt}{dx} = \frac{1}{\frac{dx}{dt}}\), we have \(\frac{dt}{dx} = \frac{1}{3}\)
4. Therefore, \(\frac{dy}{dx} = -7 \times \frac{1}{3} = -\frac{7}{3}\)
**Conclusion:**
- The derivative \(\frac{dy}{dx}\) is \(-\frac{7}{3}\).
**Additional Resources:**
If you need further assistance, there's a "Need Help?" section with a "Read It" button for more detailed guidance.
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