Compute the height of oil column if density of oil is 900 km/m3, density of water is 1000 kg/m3 and the difference in levels between points A and B of 10 cm. The image depicts a U-shaped tube with two fluids, oil and water, demonstrating concepts related to fluid statics. The left side of the tube contains a layer of oil above water, with a point labeled A within the oil layer. The right side of the tube is filled solely with water, with a point labeled B at the top of the water column.Key Elements:- **Left Side of the U-Tube:** - The left arm is divided into two sections: oil on top and water below. - Point A is located within the oil layer. - The interface between oil and water is clearly marked.- **Right Side of the U-Tube:** - The right arm contains only water, reaching up to point B at the top.- **Gravity:** - An arrow labeled "g" points downward, indicating the direction of gravitational force.The diagram effectively shows how different fluids behave in a connected tube under the influence of gravity, illustrating principles such as fluid equilibrium and pressure differences due to varying fluid densities.

Name: Compute the height of oil column if density of oil is 900 km/m3, densi
Uploaded: 2024-03-20T06:56:55.000Z
Channel: Bartleby
Description: Compute the height of oil column if density of oil is 900 km/m3, density of water is 1000 kg/m3 and the difference in levels between points A and B of 10 cm. The image depicts a U-shaped tube with two fluids, oil and water, demonstrating concepts rel

Given density -> oil -> Po = 900 kgm3 (Assuming B above point A )water-> Pw = 1000 kgm3 Difference in height of B and A point is 10cmTherefore, at the interface of AB. Both side pressure are equal.PA+PO×g×h=PB+PW×g×10100+Pwghnow,PA =PB =atmospheric pressure=PO×g×h-PW×g×h =PB -PA+PW×g×10100=(900-1000)×h =0+1000 ×10100= h =-1mTherefore, h =1m and from our assumption that B is above A is false.Height of oil column will be 1m and water column be 0.9mVerify:At point AB -> oil column pressure =900×g×1 =900g water column pressure =1000×g×0.9=900g